Tìm x nhé

a, 100   b, 45   c, -20   d, 46.

a,100

b,45

c,-20

d,46

a, 100   b, 45   c, -20   d, 46

a) \(42-13< 30\)

\(70-25=45\)

b) \(52-15< 60-15\)

\(54-17>45-17\)

\(=\dfrac{5}{12}+\left(\dfrac{8}{17}+\dfrac{60}{17}\right)\\ =\dfrac{5}{12}+4=4\dfrac{5}{12}\)

=512+(817+6017)=512+4=4512

60 +12 + (-17) + (-43) = 60 + [(-17) + (-43)] +12 = 12

a) 24 + 17 + 26 = (24 + 26) + 17

                         = 50 + 17

                         = 67

b) 80 + 310 + 120 + 90 = (80 + 120) + (310 + 90)

                                    = 200 + 400

                                     = 600

c) 34 + 140 + 60 + 16 = (34  + 16) + (140 + 60)

                                  = 50 + 200

                                  = 250

+)\(\frac{7}{30}=\frac{7\cdot4}{30\cdot4}=\frac{28}{120}\)\(\frac{7}{30}=\frac{7\cdot4}{30\cdot4}=\frac{28}{120}\); \(\frac{13}{60}=\frac{13\cdot2}{60\cdot2}=\frac{26}{120}\)

\(\frac{-9}{40}=\frac{\left(-9\right)\cdot3}{40\cdot3}=\frac{-27}{120}\)

\(\frac{17}{60}=\frac{17\cdot3}{60\cdot3}=\frac{51}{180}\) ; \(\frac{-5}{18}=\frac{\left(-5\right)\cdot10}{18\cdot10}=\frac{-50}{180}\)

\(\frac{-64}{90}=\frac{\left(-64\right)\cdot2}{90\cdot2}=\frac{-128}{180}\)

a) (-12) + 25 + 75 + 12 = (-12) + 12 + 25 + 75 = 0 +100 = 100.

b) 60 +12 + (-17) + (-43) = 60 + [(-47) + (-43)] +12.

c) (-2) + (-87) + (-18) + 87 = [(-2) + (-18)] + [(-87) + 87].

d) (-1)+(-2) + 36 + (-17) = 36+[(-1) + (-2) + (-17)].

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