- 4=123456789
- 5=0123
- 123456789=5
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4 × 6 = 24 4 × 4 = 16 5 × 4 = 20 5 × 8 = 40 |
2 × 4 = 8 4 × 7 = 28 5 × 6 = 30 5 × 2 = 10 |
4 × 9 = 36 4 × 8 = 32 5 × 7 = 35 5 × 3 = 15 |
3 × 4 = 12 4 × 10 = 40 5 × 10 = 50 5 × 9 = 45 |
4 x 6 = 24 4 x 4 = 16 5 x 4 = 20 5 x 8 = 40
2 x 4 = 8 4 x 7 = 28 5 x 6 = 30 5 x 2 = 10
4 x 9 = 36 4 x 8 = 32 5 x 7 = 35 5 x 3 = 15
3 x 4 = 12 4 x 10 = 40 5 x 10 = 50 5 x 9 = 45
Lời giải chi tiết:
5 – 2 < 4 | 5 – 4 < 2 | 4 + 1 = 5 |
5 – 2 = 3 | 5 – 3 > 1 | 5 – 1 < 5 |
5 – 2 > 2 | 5 – 1 = 4 | 5 – 4 > 0 |
Lời giải chi tiết:
5 + 5 = 10 | 10 = 4 + 6 | 5 < 10 – 4 |
5 + 4 < 10 | 6 + 4 > 4 + 5 | 6 > 9 – 4 |
5 + 5=10 | 10= 4 + 6 | 5 <10 – 4 |
5 + 4 >10 | 6 + 4 > 4 + 5 | 6 > 9 – 4 |
D=5/4+5/4^2+5/4^3+....+5/4^99
4D=4(5/4+5/4^2+5/4^3+....+5/4^99)
4D=5+5/4+5/4^2+5/4^3+....+5/4^98
Lấy 4D-D=(5+5/4+5/4^2+5/4^3+....+5/4^98)-(5/4+5/4^2+5/4^3+....+5/4^99)
=>3D=5-5/4^99
D=5/3-5/3x4^99<5/3
=>d<5/3(ĐPCM)
`Answer:`
\(D=\frac{5}{4}+\frac{5}{4^2}+\frac{5}{4^3}+\frac{5}{4^4}+...+\frac{5}{4^{99}}\)
\(\Rightarrow4D=5+\frac{5}{4}+\frac{5}{4^2}+\frac{5}{4^3}+...+\frac{5}{4^{98}}\)
\(\Rightarrow4D-D=\left(5+\frac{5}{4}+\frac{5}{4^2}+\frac{5}{4^3}+...+\frac{5}{4^{98}}\right)-\left(5+\frac{5}{4^2}+\frac{5}{4^3}+\frac{5}{4^4}+...+\frac{5}{4^{99}}\right)\)
\(\Rightarrow3D=5-\frac{5}{4^{99}}\)
\(\Rightarrow D=\left(5-\frac{5}{4^{99}}\right):3\)
\(\Rightarrow D=\frac{5}{3}-\frac{5}{4^{99}.3}< \frac{5}{3}\)
Vậy `D<5/3`
Sửa đề: 3^5+3^5+3^5; 2^x
=>\(2^x=\dfrac{4^5\cdot4}{3^5\cdot3}\cdot\dfrac{6^5\cdot6}{2^5\cdot2}\)
=>\(2^x=\left(\dfrac{4}{3}\right)^6\cdot\left(\dfrac{6}{2}\right)^6=4^6=2^{12}\)
=>x=12
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