2011+5[300-(17-7)²]

=2011+5[300-100]

=2011+5.200

=3011

• 2011+5[300-(17-7)²]
• =2011+5[300-100] 
• =2011+5+200
• =2011+205 

=2216 

Ta có: \(2011+5\left[300-\left(17-7\right)^2\right]\)

\(=2011+5\left[300-10^2\right]\)

\(=2011+1000=3011\)

\(2011+5.\left[300-\left(17-7\right)^2\right]\) 

\(=2011+5.\left[300-\left(10\right)^2\right]\) 

\(=2011+5.\left[300-100\right]\) 

\(=2011+5.200\) 

\(=2011+1000\) 

\(=3011\)

a, \(\left(-17\right)+5+8+17+\left(-3\right)\)

\(=\left(-17+17\right)+\left[5+\left(-3\right)\right]+8\)

\(=0+8+8=8+8=16\)

b, \(\left(5^{19}:5^{17}+3\right):7=\left(5^2+3\right):7\)

\(=\left(25+3\right):7=28:7=4\)

c, \(|-8|+\left(-5\right)+9+\left(-7\right)+|-4|\)

\(=8-5+9-7+4=3+2+4=5+4=9\)

ý d mk ko biết nha.

thông cảm cho mk nha.

k mk nha.

#mon

2011 + 5.[300 - (17 - 7)²]

= 2011 + 5.(300 - 10²)

= 2011 + 5.(300 - 100)

= 2011 + 5.200

= 2011 + 1000

= 3011

bạn gặp đúng người đấy.Kết quả đúng nhất là 3011,nếu sai mình chịu gì cũng được

c: \(\Leftrightarrow\left\{{}\begin{matrix}8x-2\left|y+2\right|=6\\x+2\left|y+2\right|=3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}9x=9\\x+2\left|y+2\right|=3\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=1\\y+2\in\left\{1;-1\right\}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y\in\left\{-1;-3\right\}\end{matrix}\right.\)

a: \(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{4}{x-3}=2\\\dfrac{1}{2\left|y\right|-3}=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x-3=2\\2\left|y\right|=4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=5\\y\in\left\{2;-2\right\}\end{matrix}\right.\)

\(2011+5\left[300-\left(17-7\right)^2\right]\)

\(=2011+5\left[300-10^2\right]\)

\(=2011+5\left[300-100\right]\)

\(=2011+5.200\)

\(=2011+1000\)

\(=3011\)

học tốt 

a: \(=2011+5\cdot\left[300-10^2\right]\)

\(=2011+5\cdot200\)

=1011

b: \(=695-\left[200+10^2\right]\)

=695-300

=395

a) =2011+5.200

    =3011

b)=695-300

   =395

c)1=29-5.4

     =109

d)=2010-2000:400

  =2010-5

  =2005

\(\frac{\frac{2}{7}+\frac{2}{17}+\frac{2}{37}}{\frac{5}{7}+\frac{5}{17}+\frac{5}{37}}\)

\(=\frac{2\left(\frac{1}{7}+\frac{1}{17}+\frac{1}{37}\right)}{5\left(\frac{1}{7}+\frac{1}{17}+\frac{1}{37}\right)}\)

\(=\frac{2}{5}\)

2/7+2/17+2/37/ 5/7+5/17+5/37

= 2(1/7+1/17+1/37)/ 5(1/7+1/17+1/37)

= 2/5

# HỌC TỐT #

tk nha