1 + 1³ + 1⁴ + ............. + 1⁹⁸ + 1⁹⁹ (98 số hạng)

= 1 + 1 + 1 + 1 + .......... + 1 (98 số hạng)

= 98 . 1

= 98

=970200

( 100 - 1 ) ( 100 - 2 ) ( 100 - 3 )

= 99 . 98 . 97

= 941094

Ta có: 99x99=99x(98+1) = 99x98+99

98x100= 98x(99+1) = 98x99+98

Ta có: 98x99=98x99 mà 99> 98 => 99x99>98x100

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

=-5145

k mk nha bn

-39 . ( 5 - 99 ) + 99 . ( 10 - 99 )

= ( -39 ) . ( -94 ) + 99 . ( -89 )

= 3666 + ( -8811 ) 

= -5145

m = 1 + ( -2 ) + 3 + ( -4 ) + ....... + ( - 2016 ) + 2017

m = [ 1 + ( - 2 ) ] + [ 3 + ( -4 ) ] + ...... + [ 2015 + ( -2016 ) + 2017

m =    ( -1 ) + ( -1 ) + ...... + ( -1 ) + 2017

         có 1008 số -1

m = ( -1 ) x 1008 + 2017

m = ( -1008 ) + 2017 

, = 1009

Ta có :

m = 1 + ( -2 ) + 3 + ( -4 ) + ....... + ( - 2016 ) + 2017

m = [ 1 + ( - 2 ) ] + [ 3 + ( -4 ) ] + ...... + [ 2015 + ( -2016 ) + 2017

m = ( -1 ) + ( -1 ) + ...... + ( -1 ) + 2017 [ có 1008 số -1 ]

m = ( -1 ) x 1008 + 2017

m = ( -1008 ) + 2017 

m = 1009

\(\dfrac{1}{4}-\dfrac{1}{3}+\dfrac{5}{12}\\ =\dfrac{3}{12}-\dfrac{4}{12}+\dfrac{5}{12}\\ =\dfrac{3-4+5}{12}\\ =\dfrac{4}{12}\\ =\dfrac{1}{3}\)