a.2xy^2-4 b.x^2+x-y^2+y c.x^2y-6xy-9y d.x^2+4x+3
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DT
2
4 tháng 2 2023
a: 2x^2y-50xy=2xy(x-25)
b: 5x^2-10x=5x(x-2)
c: 5x^3-5x=5x(x^2-1)=5x(x-1)(x+1)
d: \(x^2-xy+x=x\left(x-y+1\right)\)
e: x(x-y)-2(y-x)
=x(x-y)+2(x-y)
=(x-y)(x+2)
f: 4x^2-4xy-8y^2
=4(x^2-xy-2y^2)
=4(x^2-2xy+xy-2y^2)
=4[x(x-2y)+y(x-2y)]
=4(x-2y)(x+y)
f1: x^2ỹ-y^2+y
=(x-y)(x+y)+(x+y)
=(x+y)(x-y+1)
NV
Nguyễn Việt Lâm
Giáo viên
8 tháng 5 2019
Bạn ghi đề sai, hoặc các đáp án đều sai, ko có đường tròn nào đi qua O(0;0) hết
14 tháng 8 2017
a.16x-5x2-3 = - ( 5x2-16x+3) = -( 5x2-15x-x+3)= -[ 5x(x-3)-(x-3)] = -(5x-1)(x-3)
b.x^3-x+3x^2y+3xy^2+y^3-y = \(\left(x^3+3x^2y+3xy^2+y^3\right)-\)\(\left(x+y\right)\)
\(=\left(x+y\right)^3-\left(x+y\right)=\)\(\left(x+y\right)\left[\left(x+y\right)^2-1\right]\)
\(=\left(x+y\right)\left(x^2+2xy+y^2-1\right)\)
c.x^4+8x = \(x\left(x^3+8\right)=x\left(x+2\right)\left(x^2-2x+4\right)\)
d.x^2+x-6 = \(x^2+3x-2x-6=x\left(x+3\right)-2\left(x+3\right)\)
\(=\left(x+3\right)\left(x-2\right)\)
e.5x^2-10xy+5y^2-20z^2\(=5\left(x^2-2xy+y^2-4z^2\right)\)
\(=5\left[\left(x-y\right)^2-\left(2z\right)^2\right]\)
\(=5\left(x-y+2z\right)\left(x-y-2z\right)\)
f.2(x^5)-x^2-5x ( mik ko bik làm)
g.x^3-3x^2-4x+12 = \(x^2\left(x-3\right)-4\left(x-3\right)=\left(x^2-2^2\right)\left(x-3\right)\)
\(=\left(x-2\right)\left(x+2\right)\left(x-3\right)\)
h.x^4-5x^2+4 \(=\left(x^2\right)^2-4x^2+4-x^2\)
\(=\left(x^2-2\right)-x^2=\left(x^2-2+x\right)\left(x^2-2-x\right)\)
18 tháng 7 2021
a) Ta có: \(x^2-2xy+y^2-2x+2y\)
\(=\left(x-y\right)^2-2\left(x-y\right)\)
\(=\left(x-y\right)\left(x-y-2\right)\)
b) Ta có: \(x^2-4x+4-x^2y+2xy\)
\(=\left(x-2\right)^2-xy\left(x-2\right)\)
\(=\left(x-2\right)\left(x-2-xy\right)\)
15 tháng 10 2018
a) \(x^3+x^2y-x^2z-xyz\)
\(=x^2\left(x+y\right)-xz\left(x+y\right)\)
\(=\left(x+y\right)\left(x^2-xz\right)\)
\(=x\left(x+y\right)\left(x-z\right)\)
b) \(x^2-6x+9-9y^2\)
\(=\left(x^2-2\cdot x\cdot3+3^2\right)-\left(3y\right)^2\)
\(=\left(x-3\right)^2-\left(3y\right)^2\)
\(=\left(x-3-3y\right)\left(x-3+3y\right)\)
c) \(x^2+9x+20\)
\(=x^2+5x+4x+20\)
\(=x\left(x+5\right)+4\left(x+5\right)\)
\(=\left(x+5\right)\left(x+4\right)\)
d) \(x^4+4\)
\(=\left(x^2\right)^2+2\cdot x^2\cdot2+4-2\cdot x^2\cdot2\)
\(=\left(x^2+2\right)-\left(2x\right)^2\)
\(=\left(x^2-2x+2\right)\left(x^2+2x+2\right)\)
A
15 tháng 10 2018
a/\(x^3+x^2y-x^2z-xyz\)
\(=\left(x^3-x^2y\right)+\left(x^2y-xyz\right)\)
\(=x^2\left(x-z\right)+xy\left(x-z\right)\)
\(=\left(x-z\right)\left(x^2+xy\right)\)
b/\(x^2-6x+9-9y^2\)
\(=\left(x^2-6x+9\right)-9y^2\)
\(=\left(x-3\right)^2-\left(3y\right)^2\)
\(=\left(x-3+3y\right)\left(x-3-3y\right)\)
c/\(x^2+9x+20\)
\(=x^2+4x+5x+20\)
\(=\left(x^2+4x\right)+\left(5x+20\right)\)
\(=x\left(x+4\right)+5\left(x+4\right)\)
\(=\left(x+5\right)\left(x+4\right)\)
d/\(x^4+4\)
\(=x^4+4x^2-4x^2+4\)
\(=\left(x^2+4x^2+4\right)-4x^2\)
\(=\left(x+2\right)^2-\left(2x\right)^2\)
\(=\left(x+2-2x\right)\left(x+2+2x\right)\)
2 tháng 1 2023
a: =(x^2-x+1)(x^2+x+1)
b: =x^2-6xy+9y^2=(x-3y)^2
c: =5x(x^2-2xy+y^2)
=5x(x-y)^2
d: =(x-3)^2
e: =(2y-z)(4x+7y)
2 tháng 1 2023
a)HĐT:(x^2+1-x)(x^2+1+x)
b)=x^2-2.x.3y+(3y)^2
c)=5x(x^2-2xy+y^2)
=5x(x-y)^2
d)x^2-2.3.x+3^2
=(x-3)^2
e)(2y-z)+7y(2y-z)
=(2y-z)(1+7y)
\(a,=2\left(xy^2-2\right)\\ b,=\left(x-y\right)\left(x+y\right)+\left(x+y\right)=\left(x-y+1\right)\left(x+y\right)\\ c,=y\left(x^2-6x-9\right)\\ d,=x^2+3x+x+3=x\left(x+3\right)+\left(x+3\right)=\left(x+1\right)\left(x+3\right)\)