Tìm số nguyên x, biết:
6 + 2.(x - 19) = 16
(-240) : x – 16 = 64
2x3 = 16
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16< x < 19
vì 16 < 17 < 18 < 19
vậy x = 17; 18
vì x là số chẵn vậy x = 18
Chọn C. 18
Tìm số nguyên x, biết:
1) -16 + 23 + x = - 16
7+x=-16
x=-16-7
x=-23
2) 2x – 35 = 15
2x=15+35
2x=50
x=50:2
x=25
3) 3x + 17 = 12
3x=12-17
3x=-5
x=-5/3
4) (2x – 5) + 17 = 6
2x-5=6-17
2x-5=-11
2x=-11+5
2x=-6
x=-6:2
x=-3
5) 10 – 2(4 – 3x) = -4
2(4-3x)=10-(-4)
2(4-3x)=14
4-3x=14:2
4-3x=7
3x=4-7
3x=-3
x=-3:3
x=-1
6) - 12 + 3(-x + 7) = -18
3(-x+7)=-18-(-12)
3(x+7)=-6
x+7=-6:3
x+7=-2
x=-2-7
x=-9
a) \(\dfrac{x}{-6}=\dfrac{-15}{45}\)
\(\dfrac{-x}{6}=\dfrac{-15}{45}\)
\(\dfrac{x}{6}=\dfrac{15}{45}\)
\(x=\dfrac{\left(15\cdot6\right)}{45}\)
\(x=2\)
b) \(\dfrac{x}{5}=\dfrac{16}{25}\)
\(x=\dfrac{\left(16\cdot5\right)}{25}\)
\(x=\dfrac{80}{25}\)
\(x=\dfrac{16}{5}\)
c) \(\dfrac{5}{x-3}=\dfrac{20}{-12}\)
\(x-3=\dfrac{\left(5\cdot-12\right)}{20}\)
\(x-3=-3\)
\(x=\left(-3\right)+3\)
\(x=0\)
d) \(\dfrac{2}{5}\cdot x=\dfrac{6}{35}\)
\(x=\dfrac{6}{35}\div\dfrac{2}{5}\)
\(x=\dfrac{3}{7}\)
( x+16) : x * 12 = 240 - 180 = 60
( x+16) : x = 60 : 12 = 5
x + 16 = 5 * x = (1 + 4) * x = x + (4 * x)
16 = 4 * x
x = 16 : 4 = 4
\(1,\dfrac{x}{9}=-\dfrac{16}{36}\)
\(\Leftrightarrow36x=-16\times9\)
\(\Leftrightarrow36x=-144\)
\(\Leftrightarrow x=-144:36\)
\(\Leftrightarrow x=-4\)
\(2,\dfrac{7}{x}=\dfrac{21}{-39}\)
\(\Leftrightarrow21x=7\times\left(-39\right)\)
\(\Leftrightarrow21x=-273\)
\(\Leftrightarrow x=-273:21\)
\(\Leftrightarrow x=-13\)
\(3,\dfrac{x}{5}=\dfrac{6}{-10}\)
\(\Leftrightarrow-10x=5\times6\)
\(\Leftrightarrow-10x=30\)
\(\Leftrightarrow x=3\)
1. \(\text{6 + 2.(x - 19) = 16}.\)
\(\Leftrightarrow2.\left(x-19\right)=10.\)
\(\Leftrightarrow x-19=5.\)
\(\Leftrightarrow x=24.\)
Vậy \(x=24.\)
2. \(\text{(-240) : x – 16 = 64}.\)
\(\Leftrightarrow\left(-240\right):x=80.\)
\(\Leftrightarrow x=-3.\)
Vậy \(x=-3.\)
3. \(2x^3=16.\)
\(\Leftrightarrow x^3=8.\)
\(\Leftrightarrow x=2.\)
Vậy \(x=2.\)
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(2x – 3)^2 = 49