2 = 1 + 1     6 = 2 + 4     8 = 5 + 3     10 = 8 + 2

3 = 1 + 2     6 = 3 + 3     8 = 4 + 4     10 = 7 + 3

4 = 3 + 1     7 = 1 + 6     9 = 8 + 1     10 = 6 + 4

4 = 2 + 2     7 = 5 + 2     9 = 6+ 3     10 = 5 + 5

5 = 4 + 1     7 = 4 + 3     9 = 7 + 2     10 = 10 + 0

5 = 3 + 2     8 = 7 + 1     9 = 5 + 4     10 = 0 + 10

6 = 5 + 1     8 = 6 + 2     10 = 9 + 1     1 = 1 + 0

Tiếng  việt  khó .

215

215

a: \(=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot\dfrac{5}{4}=\dfrac{5}{2}\)

b: \(=\dfrac{1}{5}\cdot10-\dfrac{1}{3}\cdot\dfrac{24-45}{20}=2-\dfrac{-7}{20}=2+\dfrac{7}{20}=\dfrac{47}{20}\)

c: \(=\dfrac{-7}{8}\cdot\dfrac{16}{21}-\dfrac{3}{5}\cdot\dfrac{-1}{2}\)

\(=\dfrac{-2}{3}+\dfrac{3}{10}=\dfrac{-20+9}{30}=\dfrac{-11}{30}\)

( 1+ 1/2 ) . ( 1+ 1/3 ) . ( 1+ 1/4 )=5/2

1/5 : 1/10 - 1/3 ( 6/5 - 9/4 )=47/20

-7/8 : 21/16 - 3/5 . ( 1/5 - 7/10 ) =-11/30

=2+200+1/3+1

=203+1/3

=610/3

Viết đổi 10/10 cuối vô duyên quá! và dấu của các phân số có mẫu 10 phải là -.

Sửa đi, Linh làm cho.

????????????????????????????????????????????????????

\(\frac{\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{5}\right):\left(\frac{1}{2}+\frac{1}{4}-\frac{1}{5}\right)}{\left(\frac{1}{2}+\frac{1}{5}+\frac{1}{10}\right):\left(\frac{1}{2}+\frac{1}{5}-\frac{1}{10}\right)}=\frac{\frac{9}{20}:\frac{11}{20}}{\frac{4}{5}:\frac{3}{5}}=\frac{\frac{9}{11}}{\frac{4}{3}}=\frac{27}{44}\)

bạn hãy làm bài này một cách nhanh hơn được ko ?

5+1+1+1+1+1+1+1+1+1+1*10*10*0+1

=0+1

=1

5+1+1+1+1+1+1+1+1+1+1*10*10*0+1

= 15

`Answer:`

\dfrac15+\dfrac1{5+10}+\dfrac1{5+10+15}\ +\,.\!.\!.+\ \dfrac1{5+10+15\ +\,.\!.\!.+\ 100}\\=\dfrac15+\dfrac1{5.(1+2)}+\dfrac1{5.(1+2+3)}\ +\,.\!.\!.+\ \dfrac1{5.(1+2+3\ +\,.\!.\!.+\ 20)}\\=\dfrac15\left(1+\dfrac1{1+2}+\dfrac1{1+2+3}\ +\,.\!.\!.+\ \dfrac1{1+2+3\ +\,.\!.\!.+\ 20}\right)\\=\dfrac15\bigg(\dfrac22+\dfrac26+\dfrac2{12}\ +\,.\!.\!.+\ \dfrac2{20.21}\bigg)\\=\dfrac25\left(\dfrac1{1.2}+\dfrac1{2.3}+\dfrac1{3.4}\ +\,.\!.\!.+\ \dfrac1{20.21}\right)\\=\dfrac25\left(1-\dfrac12+\dfrac12-\dfrac13+\dfrac13-\dfrac14\ +\,.\!.\!.+\ \dfrac1{20}-\dfrac1{21}\right)\\=\dfrac25\left(1-\dfrac1{21}\right)\\=\dfrac25\!\cdot\!\dfrac{20}{21}\\=\dfrac8{21}

`Answer:`

Mình gửi lại bài nhé. Mong lần này không bị lỗi như lần trước.

\(\dfrac15+\dfrac1{5+10}+\dfrac1{5+10+15}\ +\,.\!.\!.+\ \dfrac1{5+10+15\ +\,.\!.\!.+\ 100}\\=\dfrac15+\dfrac1{5.(1+2)}+\dfrac1{5.(1+2+3)}\ +\,.\!.\!.+\ \dfrac1{5.(1+2+3\ +\,.\!.\!.+\ 20)}\\=\dfrac15\left(1+\dfrac1{1+2}+\dfrac1{1+2+3}\ +\,.\!.\!.+\ \dfrac1{1+2+3\ +\,.\!.\!.+\ 20}\right)\\=\dfrac15\bigg(\dfrac22+\dfrac26+\dfrac2{12}\ +\,.\!.\!.+\ \dfrac2{20.21}\bigg)\\=\dfrac25\left(\dfrac1{1.2}+\dfrac1{2.3}+\dfrac1{3.4}\ +\,.\!.\!.+\ \dfrac1{20.21}\right)\\=\dfrac25\left(1-\dfrac12+\dfrac12-\dfrac13+\dfrac13-\dfrac14\ +\,.\!.\!.+\ \dfrac1{20}-\dfrac1{21}\right)\\=\dfrac25\left(1-\dfrac1{21}\right)\\=\dfrac25\!\cdot\!\dfrac{20}{21}\\=\dfrac8{21}\)