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bạn có thể giải chi tiết giúp mình được ko 

\(A=2,53\times17+17,67\times15+2,53\times83+17,67\times85\)

\(A=2,53\times17+2,53\times83+17,67\times15+17,67\times85\)

\(A=2,53\times\left(17+83\right)+17,67\times\left(15+85\right)\)

\(A=2,53\times100+17,67\times100\)

\(A=253+1767\)

\(A=2020\)

Tìm y biết y : 10 + y × 3,9 =4,8

=1358 x (15+85)+358x(590-490)

=1358x100+358x100

=100x(1358+358)

=100x1716

=171600

= 1358 x ( 15 + 85) + 358 x ( 590 - 490)

= 1358 x 100 + 358 x 100

= 100 x ( 1358 + 358 ) 

= 100 x 1716 = 171600

\(A=468+15\times468+85\times468\\ =468\times\left(1+15+85\right)\\ =468\times101\\ =47268\)

Em xem lại đề câu này không thể tính nhanh được.

\(A=468+15x468+85x468\\ A=468x\left(15+85+1\right)\\ A=468x101\\ A=47268\)

1.100x15+85x100

=1500+8500

=10000

2.100x198-100x98

=19800-9800

=10000

3.50+5-15+10

=55-25

=30

1)=10000

2)=10000

3)=50

A = 85^2 + 170.15 + 225;
=85^2+2.85.15+15^2
=(85+15)^2
=100^2
=10000

A= 85²+170 x 15 + 225

A=7225+225+2550

A=7450+2550

A=10000

85 x 72,5 + 15 x 72,5

= 72,5 x ( 85 + 15 )

= 72,5 x 100 

= 72,500

= 72,5 x (85+15)

=72,5 x100

= 7250

k mk nhoa

3 x 15 + 21 x 15 + 85 x 5

= 45 + 315 + 425

= 785

15 - 30 + 40 

= 25

21 + 19 - 50 + 10

= 0

\(\dfrac{1}{5}-\dfrac{1}{4}+2\)

\(=-\dfrac{1}{20}+2\)

\(=\dfrac{39}{20}\)

\(\left(\dfrac{1}{4}+\dfrac{1}{6}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\)

\(=\dfrac{5}{12}\times\dfrac{1}{4}\)

\(=\dfrac{5}{12}\times\dfrac{3}{12}\)

\(=\dfrac{5}{48}\)

\(\dfrac{1}{10}+\dfrac{1}{5}-\dfrac{3}{4}\)

\(=-\dfrac{9}{20}\)

\(3\times15+21\times15+85\times5\\ =15\times\left(3+21\right)+425\\ =15\times24+425\\ =360+425\\ =785\)

\(15-30+40\\ =\left(15+40\right)-30\\ =55-30\\ =25\)

\(21+19-50+10\\ =\left(21+19\right)-\left(50-10\right)\\ =40-40\\ =0\)

\(\dfrac{1}{5}-\dfrac{1}{4}+2\)

\(=\dfrac{4}{20}-\dfrac{5}{20}+\dfrac{40}{20}\)

\(=\dfrac{\left(4+40\right)}{20}-\dfrac{5}{20}\)

\(=\dfrac{44}{20}-\dfrac{5}{20}\)

\(=\dfrac{39}{20}\)

\(\left(\dfrac{1}{4}+\dfrac{1}{6}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\)

\(=\dfrac{5}{12}\times\dfrac{1}{4}\)

\(=\dfrac{5}{48}\)

\(\dfrac{1}{10}+\dfrac{1}{5}-\dfrac{3}{4}\)

\(=\dfrac{2}{20}+\dfrac{4}{20}-\dfrac{15}{20}\)

\(=\dfrac{6}{20}-\dfrac{15}{20}\)

\(=-\dfrac{9}{20}\)