(-180-23) - (20-180) + (-250) x (-4)

= (- 203) - (-160) + 1000

=  (-43) + 1000

=957

1) 125.(-24) + 24.225.

\(=24\left(-125+225\right)=24.100=2400.\)

2) 512.(2 – 128) – 128. (-512).

\(=512\left(2-128+128\right)=512.2=1024.\)

\(\frac{20}{11}\times\frac{33}{23}\times\frac{69}{180}=\frac{20}{11}\times\left(\frac{33}{23}\times\frac{23}{60}\right)\)

=\(\frac{20}{11}\times\frac{759}{1380}=\frac{20}{11}\times\frac{11}{20}=\frac{220}{220}=1\)

\(\frac{20}{11}\)x    \(\frac{33}{23}\)x   \(\frac{69}{180}\)=  1

 ( 675,98 + 888,66 + 111,34 ) x 0,01 = 16,7598

20/11*33/23*69/180=1/1*3/1*3/9=1 

\(\frac{20}{11}\cdot\frac{33}{23}\cdot\frac{69}{180}=\frac{20\cdot33\cdot69}{11\cdot23\cdot180}=\frac{9}{9}=1\)

a) 20/11x33/23x69/180=20/11x11x3/23x23x3/20x9=9        ( 11x3=33  23x3=69   20x9=180  )

b)(675,98+888,66+111,34)x0,01

=(675,98+1000)x0,01

=1675,98x1/100

=16,7598

a) dùng triệt tiêu ta sẽ được 1=> a)=1

a)

\(\frac{20}{11}.\frac{33}{23}.\frac{69}{180}\)

\(=\left(\frac{20}{11}.\frac{69}{180}\right).\frac{33}{23}\)

\(=\frac{23}{33}.\frac{33}{23}=1\)

b)  0,8 x 96 + 0,8 x 2 x 2

=0,8 x ( 96+2+2)

=0,8 x 100

= 80

a) 20/11 x 33/23 x 69/180 = 60/23 x 69/180 = 1

b) 0,8 x 96 + 0,8 x 2 x 2 = 0,8 x ( 96 + 2 ) x 2 = 0,8 x 98 x 2 = 78,4 x 2 = 156,8

\(\frac{20}{11}\times\frac{33}{23}\times\frac{69}{180}=\frac{20}{11}\times\left(\frac{33}{23}\times\frac{23}{60}\right)\)

\(=\frac{20}{11}\times\frac{759}{1380}=\frac{20}{11}\times\frac{11}{20}=\frac{220}{220}=1\)

$\frac{20}{11}\times \frac{33}{23}\times \frac{69}{180}=\frac{20}{11}\times \left(\frac{33}{23}\times \frac{23}{60}\right)$