A=\(\frac{\left(3\frac{2}{15}+\frac{1}{15}\right):2\frac{1}{2}}{\left(5\frac{3}{7}-2\frac{1}{4}\right):4\frac{43}{56}}\)
B=\(\frac{1,2:\left(1\frac{1}{5}\cdot1\frac{1}{4}\right)}{0,32+\frac{2}{25}}\)
Chứng minh A=B
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\(A=\frac{\left(3\frac{1}{15}+\frac{1}{5}\right):2\frac{1}{2}}{\left(5\frac{3}{7}-2\frac{1}{4}\right):4\frac{43}{56}}=\frac{\left(\frac{46}{15}+\frac{3}{15}\right):\frac{5}{2}}{\left(\frac{38}{7}-\frac{9}{4}\right):\frac{267}{56}}=\frac{\frac{49}{15}.\frac{2}{5}}{\frac{89}{28}.\frac{56}{267}}=\frac{\frac{98}{75}}{\frac{2}{3}}=\frac{49}{25}\)
\(B=\frac{1,2:\left(1\frac{1}{5}.1\frac{1}{4}\right)}{0.32+\frac{2}{5}}=\frac{\frac{6}{5}:\left(\frac{6}{5}.\frac{5}{4}\right)}{\frac{8}{25}+\frac{10}{25}}=\frac{\frac{6}{5}.\frac{4}{6}}{\frac{18}{25}}=\frac{\frac{4}{5}}{\frac{18}{25}}\)
ĐỀ SAI
A =\(\frac{\left(\frac{17}{5}+\frac{1}{5}\right).\frac{2}{5}}{\left(\frac{38}{7}-\frac{9}{4}\right).\frac{56}{267}}\)
A=\(\frac{36}{25}\).\(\frac{3}{2}\)=\(\frac{54}{25}\)=2,16
B=\(\frac{1,2:\left(\frac{6}{5}-\frac{5}{4}\right)}{0,32+\frac{2}{25}}\)=-24.\(\frac{5}{2}\)=-60
vì 2,16 > -60 Vậy A>B
Ta có
\(A=\frac{\left(3\frac{2}{5}+\frac{1}{5}\right):2\frac{1}{2}}{\left(5\frac{3}{7}-2\frac{1}{4}\right):4\frac{43}{56}}\) \(B=\frac{1,2:\left(1\frac{1}{5}-1\frac{1}{4}\right)}{0,32+\frac{2}{25}}\)
\(\Leftrightarrow A=\frac{\left(\frac{17}{5}+\frac{1}{5}\right):\frac{5}{2}}{\left(\frac{38}{7}-\frac{9}{4}\right):\frac{276}{56}}\) \(\Leftrightarrow B=\frac{\frac{6}{5}:\left(\frac{6}{5}-\frac{5}{4}\right)}{\frac{8}{25}+\frac{2}{25}}\)
\(\Leftrightarrow A=\frac{\frac{18}{5}:\frac{5}{2}}{\frac{89}{28}:\frac{276}{56}}\) \(\Leftrightarrow B=\frac{\frac{6}{5}:\left(-\frac{1}{20}\right)}{\frac{2}{5}}\)
\(\Leftrightarrow A=\frac{\frac{36}{25}}{\frac{89}{138}}\) \(\Leftrightarrow B=\frac{\frac{5}{4}}{\frac{2}{5}}\)
\(\Leftrightarrow A=\frac{4968}{2225}\) \(\Leftrightarrow B=\frac{25}{8}\)
\(\Leftrightarrow A=\frac{39744}{17800}\) \(\Leftrightarrow B=\frac{55625}{17800}\)
Ta có: 39744<55625
\(\Rightarrow A< B\)
Vậy A<B
CÓ ai giải giùm bài này đi , mình cũng có một bài tương tự mà chưa giải đc