6(x+11)-7(2x)=26
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Bài 6:
\(21,251+6,058+0,749+1,042\)
\(=\left(21,251+0,749\right)+\left(6,058+1,042\right)\)
\(=22+7,1\)
\(=29,1\)
___________________
\(1,53+5,309+12,47+5,691\)
\(=\left(1,53+12,47\right)+\left(5,309+5,691\right)\)
\(=14+11\)
\(=25\)
5:
a: =>x/17=5/17
=>x=5
b; =>6+x=7/11*33=21
=>x=15
c: \(\dfrac{12+x}{43-x}=\dfrac{2}{3}\)
=>3x+36=86-2x
=>5x=50
=>x=10
d: \(\dfrac{x}{5}< \dfrac{3}{7}\)
=>x<3/7*5
=>x<15/7
f: 15/26+x/16=46/52
=>x/16=23/26-15/26=8/26=4/13
=>x=4/13*16=64/13
\(\dfrac{26}{7}\) x \(\dfrac{11}{3}-\dfrac{26}{7}\) x \(\dfrac{2}{3}-\dfrac{6}{3}\) x \(\dfrac{26}{7}\)
\(=\dfrac{26}{7}\) x \(\left(\dfrac{11}{3}-\dfrac{2}{3}-\dfrac{6}{3}\right)\)
\(=\dfrac{26}{7}\) x \(\dfrac{3}{3}\)
\(=\dfrac{26}{7}\) x \(1=\dfrac{26}{7}\)
26/7 x 11/3 - 26/7 x 2/3 - 6/3 x 26/7
=( 11/3 - 2/3 - 6/3 ) x26/7
= 1 x 26/7
= 26 /7
Tick cho mình nha
a) 71 - (33 + x) = 26
⇔ 71 - 33 - x = 26
⇔ 38 - x = 26
⇔ x = 38 - 26
⇔ x = 12
b) (x + 73) - 26 = 76
⇔ x + 73 - 26 = 76
⇔ x + 47 = 76
⇔ x = 76 - 47
⇔ x = 29
c) 45 - (x + 9) = 6
⇔ 45 - x - 9 = 6
⇔ 36 - x = 6
⇔ x = 36 - 6
⇔ x = 30
d) 89 - (73 - x) = 20
⇔ 89 - 73 + x = 20
⇔ 16 + x = 20
⇔ x = 20 - 16
⇔ x = 4
e) (x + 7) - 25 = 13
⇔ x + 7 - 25 = 13
⇔ x - 18 = 13
⇔ x = 13 + 18
⇔ x = 31
f) 198 - (x + 4) = 120
⇔ 198 - x - 4 = 120
⇔ 194 - x = 120
⇔ x = 194 - 120
⇔ x = 74
g) 140 : (x - 8) = 7
⇔ x - 8 = 140 : 7
⇔ x - 8 = 20
⇔ x = 20 + 8
⇔ x = 28
h) 4(x + 41) = 400
⇔ x + 41 = 400 : 4
⇔ x + 41 = 100
⇔ x = 100 - 41
⇔ x = 59
i) 11(x - 9) = 77
⇔ x - 9 = 77 : 11
⇔ x - 9 = 7
⇔ x = 7 + 9
⇔ x = 16
j) 5(x - 9) = 350
⇔ x - 9 = 350 : 5
⇔ x - 9 = 70
⇔ x = 70 + 9
⇔ x = 79
k) 2x - 49 = 5.32
⇔ 2x - 49 = 45
⇔ 2x = 45 + 49
⇔ 2x = 94
⇔ x = 94 : 2
⇔ x = 47
l) 200 - (2x + 6) = 43
⇔ 200 - 2x - 6 = 64
⇔ 194 - 2x = 64
⇔ 2x = 194 - 64
⇔ 2x = 130
⇔ x = 130 : 2
⇔ x = 65
a) 71 - (33 + x) = 26
⇔ 33+x=71-26
⇔ 33 + x = 45
⇔ x = 45 - 33
⇔ x = 12
Vậy x=12
b) (x + 73) - 26 = 76
⇔ (x + 73) = 76+26
⇔ x + 73 = 102
⇔ x = 102-73
⇔ x = 29
Vậy x=29
c) 45 - (x + 9) = 6
⇔ x + 9 = 45 - 6
⇔ x+9 = 39
⇔ x = 39 - 9
⇔ x = 30
Vậy x=30
a)
\(\dfrac{6}{13}\cdot\dfrac{8}{7}\cdot\dfrac{-26}{3}\cdot\dfrac{-7}{8}\)
\(=\dfrac{6}{13}\cdot\dfrac{-26}{3}\cdot\dfrac{8}{7}\cdot\dfrac{-7}{8}\)
\(=-4\cdot\left(-1\right)\\ =4\)
b)
\(\dfrac{6}{11}+\dfrac{11}{3}\cdot\dfrac{3}{22}\)
\(=\dfrac{6}{11}+\dfrac{1}{2}\\ =\dfrac{12}{22}+\dfrac{11}{22}\\ =\dfrac{23}{22}\)
2x - 15 = -11 - ( -16 )
2x - 15 = -11 + 16
2x - 15 = 5
2x = 5 + 15
2x = 20
x = 20 : 1
x = 10
Vậy x = 10
7 - 2x = -37 - ( -26 )
7 - 2x = -37 + 26
7 - 2x = -11
2x = 7 - ( - 11 )
2x = 7+ 11
2x = 18
x = 18 : 2
x = 9
Vậy x = 9
| x + 7 | = 9
TH1 :
x + 7 = 9
=> x = 9 - 7
=> x = 2
TH2 :
x - 7 = -9
=> x = -9 - 7
=> x = - 9 + ( -7 )
=> x = -16
Vậy x = 2 và x = -16
Câu cuối bn tự làm nha! ^-^
2x-15=-11-(-16)
2x-15= -11+16
2x-15=5
2x=5+15
2x=20
x=20:2
x=10
*) \(-7+2x=-37-\left(-26\right)\)
⇔ \(-7+2x=-11\)
⇔ \(2x=\left(-11\right)-\left(-7\right)\)
⇔ \(2x=-4\)
⇔ \(x=\left(-4\right):2\)
⇔ \(x=-2\)
\(\text{(3x +9).(11-x ) =0}\)
⇔\(\left[{}\begin{matrix}3x+9=0\\11=x=0\end{matrix}\right.\)⇔\(\left[{}\begin{matrix}3x=-9\\x=11\end{matrix}\right.\)⇔\(\left[{}\begin{matrix}x=-3\\x=11\end{matrix}\right.\)
Vậy x= -3 và x= 11