(x+0,2)+(x+0.7)+...+(x+4,7)=65,5

có số x là:(4,7-0,2):0,5+1=10(số)

=> x.10+(0,2+0,7+...+4,7)=65,5

=>x.10+24,5=65,5

=>x.10=65,5-24,5

=>x.10=41

=>x     =41:10

x=4,1

vậy x=1 tí nữa mik làm tiếp cho

(x+0,2)+(x+0.7)+...+(x+4,7)=65,5

có số x là:(4,7-0,2):0,5+1=10(số)

=> x.10+(0,2+0,7+...+4,7)=65,5

=>x.10+24,5=65,5

=>x.10=65,5-24,5

=>x.10=41

=>x     =41:10

x=4,1

vậy x=1

\(a,25\%x=42,6-3,28\\ \Leftrightarrow\dfrac{1}{4}x=39,32\\ \Leftrightarrow x=157,28\)

\(b,x:40\%=7,25+6,75\\ \Leftrightarrow x:40\%=14\\ \Leftrightarrow x=5,6\)

\(c,\dfrac{7011}{25}:\left(x-42,6\right)=117,14-47,03\\ \Leftrightarrow\dfrac{7011}{25}:\left(x-42,6\right)=70,11\\ \Leftrightarrow x-42,6=4\\ \Leftrightarrow x=46,6\)

\(d,0,3\left(x+\dfrac{1}{3}\right)=\dfrac{1}{2}\cdot\left(0,81:27\right)\\ \Leftrightarrow0,3\left(x+\dfrac{1}{3}\right)=0,015\\ \Leftrightarrow x+\dfrac{1}{3}=0,05\\ \Leftrightarrow x=-\dfrac{17}{60}\)

\(a,\frac{7011}{25}:\left(x-42,6\right)=117,14-47,03\)

\(=\frac{7011}{25}:\left(x-42,6\right)=70,11\)

\(\Rightarrow\left(x-42,6\right)=\frac{7011}{25}:70,11\)

\(\Rightarrow x=4+42,6\)

\(\Rightarrow x=46,6\)

b ko co bai b a

\(\dfrac{7011}{25}:\left(x-42.6\right).15=13\)

\(\Rightarrow\dfrac{7011}{\dfrac{25}{\left(x-42,6\right)}}.0,15=13\)

\(\Rightarrow\dfrac{280,44}{\left(x-42,6\right)}.0,15=13\)

\(x-\left(280,44-42,6\right)\)

\(x=237.8+86,7\)

\(x=324,54\)

\(\)Vậy x=324,54

b.

\(7,2-\left(x+3,75:2,1\right):1,9=5,2\)

\(\Rightarrow7,2+\dfrac{-\left(x-\dfrac{3,75}{2,1}\right)}{1,9}=5,2\)

\(7,2+\dfrac{-\left(x-1,8\right)}{1,9}=5,2\)

a) 25% x X = 39.32

X = 39.32 : 25% = 9.83

b) X : 40% = 14

X = 14 x 40% = 5.6

a) 1/4 x X = 39,32

X = 39,32 : 1/4

X = 157,28

a)x=157,28                      c)x=179/7

b)x=5,6.                            d)x=1/192

Đáp án là D

Ta có 1245 + 7011 = 8256

d . 8526