a)  - 2 < x < 3 = > x ∈ {0;1;2}

b) 25 32 < x < 4 => x ∈ {1;2;3}

c) – 5 < x < - 2 = > x =  ∅

118 x 118  = 13924

118 x 188 = 35344 

k nha bn thanks @@

\(=\dfrac{117}{18}\left(\dfrac{1}{6}+\dfrac{1}{3}+\dfrac{1}{2}\right)=\dfrac{117}{18}\)

\(\dfrac{117}{118}\)

C

C.211

c - 211

câu 58: C
câu 59: A
câu 60: A

a/ \(\left(x-35\right)-120=0\)

\(\Leftrightarrow x-35=0+120\)

\(\Leftrightarrow x-35=120\)

\(\Leftrightarrow x=120+35\)

\(\Leftrightarrow x=155\)

Vậy ...

b/ \(124+\left(188-x\right)=217\)

\(\Leftrightarrow188-x=217-124\)

\(\Leftrightarrow188-x=93\)

\(\Leftrightarrow x=95\)

Vậy ...

b/ \(156-\left(x+61\right)=82\)

\(\Leftrightarrow x+61=74\)

\(\Leftrightarrow x=13\)

Vậy ..

Bằng 295240

đáp án = 295240

chúc bạn học tốt nhé

\(\dfrac{x}{y}=\dfrac{7}{20}\Rightarrow\dfrac{x}{7}=\dfrac{y}{20};\dfrac{y}{z}=\dfrac{5}{8}\Rightarrow\dfrac{y}{5}=\dfrac{z}{8}\Rightarrow\dfrac{y}{20}=\dfrac{z}{32}\\ \Rightarrow\dfrac{x}{7}=\dfrac{y}{20}=\dfrac{z}{32}\)

Áp dụng t/c dtsbn:

\(\dfrac{x}{7}=\dfrac{y}{20}=\dfrac{z}{32}=\dfrac{x+y+z}{7+20+32}=\dfrac{118}{59}=2\\ \Rightarrow\left\{{}\begin{matrix}x=14\\y=40\\z=64\end{matrix}\right.\)

Dịch k ra viết bằng ct toán đi