Ta có: \(2\left(x-1\right)-3\left(2x+2\right)-4\left(2x+3\right)=16\)

\(\Rightarrow2x-2-6x-6-8x-12=16\)

\(\Rightarrow2x-6x-8x=16+2+6+12\)

\(\Rightarrow-12x=36\)

\(\Rightarrow x=-3\)

Vậy x = -3

2x-2- 6x -6 - 8x-12=16

2x-6x-8x=2+6+12+16

-12x=36

x= -3

1: =>x^2+4x-21=0

=>(x+7)(x-3)=0

=>x=3 hoặc x=-7

2: =>(2x-5-4)(2x-5+4)=0

=>(2x-9)(2x-1)=0

=>x=9/2 hoặc x=1/2

3: =>x^3-9x^2+27x-27-x^3+27+9(x^2+2x+1)=15

=>-9x^2+27x+9x^2+18x+9=15

=>18x=15-9-27=-21

=>x=-7/6

6: =>4x^2+4x+1-4x^2-16x-16=9

=>-12x-15=9

=>-12x=24

=>x=-2

7: =>x^2+6x+9-x^2-4x+32=1

=>2x+41=1

=>2x=-40

=>x=-20

b: =>2x=16/2=8

=>x=4

a: Sửa đề: (3/2)^2x-1=(3/2)^5x-4

=>2x-1=5x-4

=>-3x=-3

=>x=1

A) \(2\left(x-1\right)-3\left(2x+2\right)-4\left(2x+3\right)=16\)

\(2x-2-6x-6-8x-12=16\)

\(2x-6x-8x-\left(2+6+12\right)=16\)

\(x.\left(2-6-8\right)-20=16\)

\(x.\left(-12\right)=16+20\)

\(x.\left(-12\right)=36\)

\(x=36:\left(-12\right)\)

\(x=-3\)

~~ học tốt ~~!!!!  >-^

a) Rút gọn được VT = 9x + 7. Từ đó tìm được x = 1.

b) Rút gọn được VT = 2x + 8. Từ đó tìm được x = 7 2 .

a: Ta có: \(\left(x+2\right)\left(x^2-2x+4\right)-x\left(x^2+2\right)=15\)

\(\Leftrightarrow x^3+8-x^3-2x=15\)

\(\Leftrightarrow2x=-7\)

hay \(x=-\dfrac{7}{2}\)

b: Ta có: \(\left(x-2\right)^3-\left(x-4\right)\left(x^2+4x+16\right)+6\left(x+1\right)^2=49\)

\(\Leftrightarrow x^3-6x^2+12x-8-x^3+64+6\left(x+1\right)^2=49\)

\(\Leftrightarrow-6x^2+12x+56+6x^2+12x+6=49\)

\(\Leftrightarrow24x=-13\)

hay \(x=-\dfrac{13}{24}\)