25/23:47/45=?
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a/[25-(-75)]+32-(32+55)
=[25+75]+32-(32+55)
=25+75+32-32-55
=[25+75]+[32-32]-55
=100+0-55
=100-55
=45
a) \(-524\cdot\left[23+\left(-45\right)\right]+524\cdot\left(-45+123\right)\)
\(=-524\cdot\left[\left(23-45\right)-\left(-45+123\right)\right]\)
\(=-524\cdot\left(23-45+45-123\right)\)
\(=-524\cdot-100\)
\(=52400\)
b) \(47\cdot69-31\cdot\left(-47\right)\)
\(=-47\cdot\left(-69-31\right)\)
\(=-47\cdot-100\)
\(=4700\)
c) \(16\left(38-2\right)-38\left(16-1\right)\)
\(=16\cdot38-16\cdot2-38\cdot16+38\)
\(=-16\cdot2+38\)
\(=-36+38\)
\(=2\)
d) \(\left(-41\right)\cdot\left(59+2\right)+59\cdot\left(41-2\right)\)
\(=-41\cdot59-41\cdot2+41\cdot59-2\cdot59\)
\(=-41\cdot2-2\cdot59\)
\(=-2\left(41+59\right)\)
\(=-2\cdot100\)
\(=-200\)
e) \(25\cdot\left(-8\right)\cdot\left(-25\right)\cdot9\cdot4\cdot100^0:3\)
\(=\left(-1000\right)\cdot\left(-25\right)\cdot9\cdot4\cdot1:3\)
\(=25000\cdot9\cdot4:3\)
\(=25000\cdot3\cdot4\)
\(=100000\cdot3\)
\(=300000\)
- \(=\left(-23+27-13+47-23+37-13+47\right):45\)\(=\left(-23.2-13.2+27.2+47.2\right):45=\left(-72+148\right):45=\frac{76}{45}\)
- \(=59:\left(111-522+115-23\right)=59:\left(-319\right)\)
Bài 3:
a: Ta có: \(23\left(42-x\right)=23\)
\(\Leftrightarrow42-x=1\)
hay x=41
b: Ta có: 15(x-3)=30
nên x-3=2
hay x=5
Bài 1:
a: 32+89+68=100+89=189
b: 64+112+236=300+112=412
c: \(1350+360+650+40=2000+400=2400\)
25/23:47/45=25/23x45/47=1125/1081
\(\frac{25}{23}:\frac{47}{45}=\frac{25}{23}x\frac{45}{47}=\frac{1125}{1081}\)
vậy \(\frac{25}{23}:\frac{47}{45}=\frac{1125}{1081}\)