1,x-43=(35-x)-48

=>x-43=35-x-48

=>x+x=35-48+43

=>2x=30

=>x=15

Vậy x=15

2,305-x+14=48+(x-23)

=>305-x+14=48+x-23

=>305+14+23-48=x+x

=>294=2x

=>x=294:2

=>x=147

3,-(x-6+85)=(x+51)-54

=>-x+6-85=x+51-54

=>6-85-51+54=x+x

=>-76=2x

=>x=(-76):2

=>x=-38

4,-(35-x)-(37-x)=33-x

=>-35+x-37+x=33-x

=>-35+(-37)+(-33)=-x-x-x

=>-105=-3x

=>x=(-105):(-3)

=>x=35

5,13-\(|x|=|-4|\)

=>13-\(|x|\)=4

=>13-4=\(|x|\)

=>9=\(|x|\)

=>x=9 hoặc x=-9

5) 13 - |x| = |-4|

=> 13 - |x| = 4

|x| = 13-4 = 9

Vậy x=9 hoặc x=-9

4) - (35-x) - (37-x) = 33-x

<=>-35 + x - 37 + x = 33-x

<=> -35 - 37 + x + x = 33-x

-72 + 2x = 33 - x

Theo quy tắc chuyển vế, ta có

-72 - 33 = - 2x + x

-105 = - (2x+x)

-105 = -3x

=> x = (-105) : (-3) = 35

Vậy x=35

Mk chỉ làm đc hai câu thôi. Mk có việc nên ko thể làm tiếp đc cho bạn nữa nha...

Ai lm hộ mk nha

Nhiều quá bạn ơi

\(37\times46+37\times51+111\)

\(=37\times46+37\times51+37\times3\)

\(=37\times\left(46+51+3\right)\)

\(=37\times100\)

\(=3700\)

------------

\(172\times47+86\times8-34\times4\)

\(=172\times47+172\times4-34\times4\)

\(=172\times\left(47+4\right)-34\times4\)

\(=172\times51-34\times4\)

\(=172\times3\times17-17\times2\times4\)

\(=17\times\left(172\times3-2\times4\right)\)

\(=17\times\left(516-8\right)\)

\(=17\times508\)

\(=8636\)

------------

\(35\times215-35\times200-175\)

\(=35\times215-35\times200-35\times5\)

\(=35\times\left(215-200-5\right)\)

\(=35\times10\)

\(=350\)

------------

\(48\times56+28\times104\)

\(=48\times2\times28+28\times104\)

\(=28\times\left(48\times2+104\right)\)

\(=28\times200\)

\(=5600\)

88 800

261 304

a: \(x-43=\left(35-x\right)-48\)

=>\(x-43=35-x-48\)

=>\(x-43=-x-13\)

=>\(x+x=-13+43\)

=>2x=30

=>x=30/2=15

b: \(305-x+14=48+\left(x-23\right)\)

=>\(319-x=48+x-23=25+x\)

=>\(x+25=319-x\)

=>\(x+x=319-25\)

=>\(2x=294\)

=>\(x=\dfrac{294}{2}=147\)

c: \(-\left(-x-6+85\right)=\left(x+51\right)-54\)

=>\(-\left(-x+79\right)=x+51-54\)

=>x-79=x-3

=>-79=-3(vô lý)

=>\(x\in\varnothing\)

d: \(-\left(35-x\right)-\left(37-x\right)=33-x\)

=>\(-35+x-37+x=33-x\)

=>2x-72=-x+33

=>\(2x+x=33+72\)

=>3x=105

=>\(x=\dfrac{105}{3}=35\)

\(25\cdot48+25\cdot51+300+25\\ =25\cdot48+25\cdot51+25\cdot12+25\cdot1\\ =25\cdot\left(48+51+12+1\right)\\ =25\cdot112=2800\)

\(x-43=35-x-48\)

\(x+x=43+35-48=30\)

2.x=30=> x=15

2) -x+6-85=x+51-54

-x-79=x-3

2x=76=> x=38

3)\(\orbr{\begin{cases}-7-x-3=-3\Rightarrow x=-7\\-7-x-3=3\Rightarrow x=-13\end{cases}}\)

`@` `\text {Ans}`

`\downarrow`

`A)`

`37 \times 46+37 \times 51+111`

`= 37 \times (46+51)+111`

`= 37 \times 97+111`

`= 3589 +111`

`= 3700`

`B)`

`35 \times 215-35 \times 210-175`

`= 35 \times (215-210)-175`

`= 35 \times 5-175`

`= 175-175=0`

`E)`

`76 \times 102-76 \times 2`

`= 76 \times (102-2)`

`= 76 \times 100`

`= 7600`

`C)`

`85 \times 94+85 \times 2 +170 \times 2`

`= 85 \times (94+2) + 170 \times 2`

`= 85 \times 96+170 \times 2`

`= 8160+340`

`= 8500`

`48 \times 56+28 \times 104`

`= 48 \times 28 \times 2+28 \times 104`

`= 28 \times (48 \times 2+104)`

`= 28 \times (96+104)`

`= 28 \times 200`

`= 5600`

`G)`

`206 \times 12-206-206`

`= 206 \times (12-1-1)`

`= 206 \times 10`

`= 2060`

a) 37 x 46 + 37 x 51 + 111

= 37 x ( 46 + 51 ) + 111

= 37 x 97 + 111

= 3589 + 111

= 3700

b) 35 x 215 - 35 x 210 - 175

= 35 x ( 215 - 210 ) - 175

= 35 x 5 - 175

= 175 - 175

= 0

e) 76 x 102 - 76 x 2

= 76 x ( 102 - 2 )

= 76 x 100

= 7600

c) 85 x 94 + 95 x 2 + 170 x 2

= 7990 + 2 x ( 95 + 170 )

= 7990 + 2 x 265

= 7990 + 530

= 8520

48 x 56 + 28 x 104

= 2688 + 2912

= 5600

g) 206 x 12 - 206 - 206

= 2472 - 206 - 206

= 2266 - 206

= 2060

Ta có : \(\dfrac{x-50}{50}+\dfrac{x-51}{49}+\dfrac{x-52}{49}+\dfrac{x-53}{47}+\dfrac{x-200}{25}=0\)

\(\Leftrightarrow\dfrac{x-50}{50}-1+\dfrac{x-51}{49}-1+\dfrac{x-52}{49}-1+\dfrac{x-53}{47}-1+\dfrac{x-200}{25}+4=0\)

\(\Leftrightarrow\dfrac{x-100}{50}+\dfrac{x-100}{49}+\dfrac{x-100}{49}+\dfrac{x-100}{47}+\dfrac{x-100}{25}=0\)

\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{25}\right)=0\)

<=> x - 100 = 0

<=> x = 100

Vậy ..

Ta có: \(\dfrac{x-50}{50}+\dfrac{x-51}{49}+\dfrac{x-52}{48}+\dfrac{x-53}{47}+\dfrac{x-200}{25}=0\)

\(\Leftrightarrow\dfrac{x-50}{50}-1+\dfrac{x-51}{49}-1+\dfrac{x-52}{48}-1+\dfrac{x-53}{47}-1+\dfrac{x-200}{25}+4=0\)

\(\Leftrightarrow\dfrac{x-100}{50}+\dfrac{x-100}{49}+\dfrac{x-100}{48}+\dfrac{x-100}{47}+\dfrac{x-100}{25}=0\)

\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{25}\right)=0\)

mà \(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{25}>0\)

nên x-100=0

hay x=100

Vậy: S={100}