Tìm số tự nhiên a, b (giả sử a > b) biết rằng: a + b = 162 và ƯCLN (a,b) = 9
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a) goi hai so la a ; b va a >b
vi UCLN(a,b)=18=>a=18k ; b=18q (trong do UCLN (k,q)=1 va k>q)
=>a+b=162
18k+18q =162
18(k+q)=162
k+q=9
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Vì \(\left(a,b\right)=9\)nên ta đặt \(a=9m,b=9n,m>n>0,\left(m,n\right)=1\).
\(a+b=9m+9n=9\left(m+n\right)=162\Leftrightarrow m+n=18\)
Ta có bảng giá trị: