a. x+23=-11

x =( -11)-23

x =-34

b. x-24=-11

x =(-11)+24

x =13

Bài 1: 

\(101\cdot125+101\cdot25-101\cdot50\)

\(=101\cdot\left(125+25-50\right)\)

\(=101\cdot100\)

\(=10100\)

Bài 2: 

\(76\cdot115+56\cdot24+59\cdot24\)
\(=76\cdot115+24\cdot\left(56+59\right)\)

\(=76\cdot115+24\cdot115\)

\(=115\cdot\left(76+24\right)\)

\(=115\cdot100\)

\(=11500\)

còn bài 3,4,5 thì sao ak 

Đề thiếu nha bn 

xin lỗi

phải là 30 x ( X + 2 ) - 6 x ( X - 5 ) - 24 x X = 100 

a) x/12 = -1/24 - 1/8

    x/12 = -1/6

    x/12 = 2/12

        x  = 2 X 12 : 12 

  Vậy x = 2

b) 2/3 . x - 1/2 .x = 5/4

          x.(2/3-1/2) = 5/4

          x.1/6       = 5/4

          x             = 5/4 :1/6

    Vậy x            = 15/2

a, x = -2

b, x = 15/2

1) \(31,5\cdot0,1+3x=7,65\)

\(\Leftrightarrow3,15+3x=7,65\)

\(\Leftrightarrow3x=4,5\)

\(\Leftrightarrow x=1,5\)

b)\(\frac{3}{8}+\left(x-\frac{5}{24}\right):\frac{2}{3}=1\)

\(\Leftrightarrow\left(x-\frac{5}{24}\right):\frac{2}{3}=\frac{5}{8}\)

\(\Leftrightarrow x-\frac{5}{24}=\frac{5}{12}\)

\(\Leftrightarrow x=\frac{5}{8}\)

1.  \(31,5.0,1+3x=7,65\)

\(\Leftrightarrow3,15+3x=7,65\)

\(\Leftrightarrow3x=4,5\)

\(\Leftrightarrow x=1,5\)

2. \(\frac{3}{8}+\left(x-\frac{5}{24}\right):\frac{2}{3}=1\)

\(\Leftrightarrow\left(x-\frac{5}{24}\right):\frac{2}{3}=\frac{5}{8}\)

\(\Leftrightarrow x-\frac{5}{24}=\frac{5}{8}.\frac{2}{3}\)

\(\Leftrightarrow x-\frac{5}{24}=\frac{5}{12}\)

\(\Leftrightarrow x=\frac{5}{8}\)

1: =>\(5^{x-2}-9=2^4-\left(6^2-6^2\right)\)

=>\(5^{x-2}=16+9=25\)

=>x-2=2

=>x=4

2: \(\Leftrightarrow3^x+16=19^6:19^5-3=19-3=16\)

=>3^x=0

=>x=0

3: \(\Leftrightarrow2^x+2^x\cdot16=272\)

=>2^x*17=272

=>2^x=16

=>x=4

4: \(\Leftrightarrow2^{x-1}+3=24-\left(4^2-2^2+1\right)=24-\left(16-4+1\right)\)

=>\(2^{x-1}+3=24-16+4-1=8+4-1=12-1=11\)

=>2^x-1=8

=>x-1=3

=>x=4

\(1,\\ a,ĐK:\left\{{}\begin{matrix}x\ge0\\x+5\ge0\end{matrix}\right.\Leftrightarrow x\ge0\\ b,Sửa:B=\left(\sqrt{3}-1\right)^2+\dfrac{24-2\sqrt{3}}{\sqrt{2}-1}\\ B=4-2\sqrt{3}+\dfrac{2\sqrt{3}\left(\sqrt{2}-1\right)}{\sqrt{2}-1}\\ B=4-2\sqrt{3}+2\sqrt{3}=4\\ 3,\\ =\left[1-\dfrac{\sqrt{x}\left(\sqrt{x}+1\right)}{1+\sqrt{x}}\right]\cdot\dfrac{\sqrt{x}-3+2-2\sqrt{x}}{\left(1-\sqrt{x}\right)\left(\sqrt{x}-3\right)}-2\\ =\left(1-\sqrt{x}\right)\cdot\dfrac{-\sqrt{x}-1}{\left(1-\sqrt{x}\right)\left(\sqrt{x}-3\right)}-2\\ =\dfrac{-\sqrt{x}-1}{\sqrt{x}-3}-2=\dfrac{-\sqrt{x}-1-2\sqrt{x}+6}{\sqrt{x}-3}=\dfrac{-3\sqrt{x}+5}{\sqrt{x}-3}\)

\(\left(2x+1\right)\left(y+2\right)=24=1.24=2.12=3.8=4.6\left(soamnua\right)\)

2x+1=1;3; (-1); (-3)

2x=-1+{1,3,-1,-3}

x={0,1,-1,-2}

y+2=24,8,-24-8

y={22,6,-26,-10}

y = {22,6 ; -26 ; -10}

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