54444

\(b.\frac{1}{3}+\frac{3}{35}< \frac{x}{210}< \frac{4}{7}+\frac{3}{5}+\frac{1}{3}\)

\(\Leftrightarrow\frac{35+9}{105}< \frac{x}{210}< \frac{60+63+35}{105}\)

\(\Leftrightarrow\frac{44}{105}< \frac{x}{210}< \frac{158}{105}\)

\(\Leftrightarrow\frac{88}{210}< \frac{x}{210}< \frac{316}{210}\)

Suy ra \(x\in\left\{89;90;100;...;313;314;315\right\}\)

\(c.\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right)-x+\frac{221}{231}=\frac{4}{3}\)

\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)-x+\frac{221}{231}=\frac{4}{3}\)

\(\Leftrightarrow\frac{1}{11}-\frac{1}{21}-x+\frac{221}{231}=\frac{4}{3}\)

\(\Leftrightarrow\frac{21-11-231x+221}{231}=\frac{308}{231}\)

\(\Leftrightarrow-231x=308-21+11-221\)

\(\Leftrightarrow-231x=77\)

\(\Leftrightarrow x=-\frac{77}{231}=-\frac{1}{3}\)

^^

Ta có:

\(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right).231-\left(3^{16}:3^{14}-2^8:2^6\right).x=2013^0\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right).231-\left(3^2-2^2\right).x=1\)

\(\left(\frac{1}{11}-\frac{1}{21}\right).231-x=1\)

\(\frac{10}{231}.231-x=1\)

\(10-x=1\)

\(x=9\)

Vậy,.............

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Đặt  \(A=\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\)

      \(A=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{19}-\frac{1}{21}\)

       \(A=\frac{1}{11}-\frac{1}{21}=\frac{10}{231}\)

thay A vào ta được:

\(\frac{10}{231}-x+\frac{23}{231}=\frac{5}{77}\) 

\(x+\frac{23}{231}=\frac{10}{231}-\frac{5}{77}=-\frac{5}{231}\)

\(x=-\frac{5}{231}-\frac{23}{231}=\frac{-4}{33}\)

\(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}-x+\frac{23}{231}=\frac{5}{77}\)\(\frac{5}{77}\)

=>\(\frac{1}{11}-\frac{1}{21}-x+\frac{23}{231}=\frac{5}{77}\)

=>\(\frac{10}{231}+\frac{23}{231}-x=\frac{5}{77}\)

=>\(\frac{33}{231}-x=\frac{5}{77}\)

=>\(\frac{1}{7}-x=\frac{5}{77}\)

=>\(\frac{11}{77}-x=\frac{5}{77}\)

=>\(x=\frac{11}{77}-\frac{5}{77}=\frac{6}{77}\)

Vậy \(x=\frac{6}{77}\)

\(\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+\frac{2}{17.19}+\frac{2}{19.21}\right)\) ) . 462 - x = 19

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\right)\) . 462 - x  = 19

\(\left(\frac{1}{11}-\frac{1}{21}\right)\) . 462 - x = 19 

... Chúc bạn học tốt !

\(\left(\frac{2}{11\cdot13}+\frac{2}{13\cdot15}+\frac{2}{15\cdot17}+\frac{2}{17\cdot19}+\frac{2}{19\cdot21}\right)\)\(\cdot462-x=19\)

\(\left(\frac{1}{11\cdot13}+\frac{1}{13\cdot15}+\frac{1}{15\cdot17}+\frac{1}{17\cdot19}+\frac{1}{19\cdot21}\right)\)\(\cdot462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\right)\)\(\cdot462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)\cdot462-x=19\)

\(\frac{10}{231}\cdot462-x=19\)

\(20-x=19\)

\(x=20-19\)

\(x=1\)

bạn nguyệt hằng giải sai rồi 1,5 chứ ko phải 15

2/11.13+2/13.15+...+2/19.21x+23/231=5/77

1/11-1/13+1/13-1/15+...+1/19-1/21x+23/231=5/77

1/11+(-1/13+1/13)+(-1/15+1/15)+...+(-1/19+1/19)-1/21x+23/231=5/77

1/11+0+0+0+...+0-1/21x+23/231=5/77

1/11-1/21x+23/231=5/77

21/231-11/231x+23/231=5/77

10/231x+23/231=5/77

10/231x           =5/77-23/231

10/231x            =15/231-23/231

10/231x             =(-8)/231

x                       =-8/231:10/231

x                       =-4/5

vậy x=-4/5

ở trên mình tính lộn.nhớ ****

\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right).462-\frac{17}{x+1,05}=19.\)

\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{21}\right)462-\frac{17}{x+1,05}=19\)

\(\Leftrightarrow20-\frac{17}{x+1,05}=19\)

\(\Leftrightarrow1-\frac{17}{x+1,05}=0\)

\(\Leftrightarrow x+1,05=17\)

\(\Leftrightarrow x=15,95\)