Đặt \(A=\frac{5}{4.6}+\frac{5}{6.8}+.....+\frac{5}{48.50}\)

\(\Leftrightarrow\frac{5}{2}A=\frac{2}{4.6}+\frac{2}{6.8}+\frac{2}{8.10}+.....+\frac{2}{48.50}\)

\(\Leftrightarrow\frac{5}{2}A=\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+....+\frac{1}{48}-\frac{1}{50}\)

\(\Leftrightarrow\frac{5}{2}A=\frac{1}{4}-\frac{1}{50}\)

\(\Leftrightarrow\frac{5}{2}A=\frac{23}{100}\Rightarrow A=\frac{23}{100}.\frac{2}{5}=\frac{23}{250}\)

Vậy câu hỏi đâu bạn ko cho thì sao mà giải

1) 3/9 + 5/9 = 8/9

2) 1/2 x 2/3 x 3/4 x 4/5

= 1/5

(1-1/2)×(1-1/3)×(1-1/4)×(1-1/5)×1-1/6=1/2×2/3×3/4×4/5×5/6=1/6

99:(3/5-3/8)

99:0,225=440

\(99:\left(\frac{3}{5}-\frac{3}{8}\right)=99:\frac{9}{40}\)

\(=440\)

@ Cừu

\(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+...+\frac{1}{98.100}\)

\(=\frac{1}{2}\left(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+....+\frac{2}{98.100}\right)\)

\(=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+....+\frac{1}{98}-\frac{1}{100}\right)\)

\(=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{100}\right)=\frac{49}{200}\)

k minh minh giai

2[1/2X4+1/4X6+1/6X8+...+1/Xx(X+2)]=11/45x2

2/2x4+2/4x6+2/6x8+....+2/Xx(X+2)=22/45

1/2-1/4+1/4-1/6+1/6-1/8+...+1/x-1/x+2=22/45

1/2-1/x+2=22/45

1/x+2=1/2-22/45

1/x+2=1/90

=>x+2=90

=>x=88

vậy x=88

\(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+...+\frac{1}{x\left(x+2\right)}=\frac{11}{45}\)

\(\Rightarrow\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+...+\frac{2}{x\left(x+2\right)}=\frac{22}{45}\)

\(\Rightarrow\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{x}-\frac{1}{x+2}=\frac{22}{45}\)

\(\Rightarrow\frac{1}{2}-\frac{1}{x+2}=\frac{22}{45}\)

\(\Rightarrow\frac{1}{x+2}=\frac{1}{2}-\frac{22}{45}\)

\(\Rightarrow\frac{1}{x+2}=\frac{1}{90}\)

=>x+2=90

=>x=90-2

=>x=88

vậy x=88

Thay 5 = x + y vào ta có:

\(\frac{2x-x-y}{x-y}+\frac{3x+x+y}{4x+y}=\frac{x-y}{x-y}+\frac{4x+y}{4x+y}=1+1=2\)

Thay \(5=x+y\)vào ta có :

\(\frac{2x-x-y}{x-y}+\frac{3x+x+y}{4x+y}\)

\(=\frac{x-y}{x-y}+\frac{4+y}{4x+y}\)

\(=1+1\)

\(=2\)