Ta có : \(B=\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)

\(=>B=\frac{\left(\frac{121}{200}+\frac{415}{1000}\right):\frac{1}{100}}{\frac{1}{12}-\frac{3725}{100}+\frac{19}{6}}\)

\(=>B=\frac{\left(\frac{121}{200}+\frac{83}{200}\right)\cdot100}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}\)

\(=>B=\frac{\frac{204}{200}\cdot100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)

\(=>B=\frac{\frac{204\cdot100}{200}}{-\frac{408}{12}}=\frac{\frac{204}{2}}{-34}=\frac{102}{-34}=-3\)

bạn biết bấm máy tính không :v

nó bằng : -3

\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}=\frac{\left(\frac{121}{200}+\frac{83}{200}\right):\frac{1}{100}}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}=\frac{\frac{51}{50}.100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)

=\(\frac{102}{-34}=-3\)

Bằng -3 nha bạn

AI GIÚP MÌNH ĐIIIII...........!MÌNH CẦN GẤP LẮM

\(-\frac{10}{17}\)

\(\frac{\frac{75}{100}:\frac{5}{2}+\left(\frac{3}{4}\right)^2-\frac{3}{4}:\frac{149}{4}}{\left(\frac{-121}{200}-\frac{83}{200}\right):\left(\frac{-1}{100}\right)}=\frac{\frac{3}{10}+\frac{9}{16}-\frac{3}{149}}{\frac{-51}{50}:\frac{-1}{100}}=\frac{\frac{69}{80}-\frac{3}{149}}{102}=0,008258487595\)

dấu / này là dấu gì vậy ?

\(\left(\frac{11}{200}+\frac{83}{200}\right):\frac{7}{75}-\frac{149}{4}+\frac{31}{6}\)

\(\frac{94}{200}:\frac{7}{75}-\frac{149}{4}+\frac{31}{6}\)

\(\frac{141}{28}-\frac{149}{4}+\frac{31}{6}\)

\(\frac{-451}{14}+\frac{31}{6}=-27\frac{1}{21}\)