x=1,281236109

x=1,281236109

chú bn hok tốt

\(\Leftrightarrow\frac{-2}{17}\le\frac{x}{17}\le\frac{2}{17}\Rightarrow x\in\left(-2;-1;0;1;2\right)\)

\(\Leftrightarrow\frac{-1}{24}\le\frac{x}{24}\le\frac{5}{24}\Rightarrow x\in\left(-1;0;1;2;3;4;5\right)\)

2 câu sau tự làm nha

\(-\frac{5}{17}+\frac{3}{17}\le\frac{x}{17}\le\frac{13}{17}+-\frac{11}{17}\)

\(\frac{-2}{17}\le\frac{x}{17}\le\frac{2}{17}\)

=> \(x\in\left\{-2;-1;0;1;2\right\}\)

\(\left(1\frac{1}{4}-\frac{3}{5}\right):\frac{17}{20}< \frac{x}{17}< \left(5\frac{1}{3}-3\frac{1}{2}\right).\frac{12}{17}\)

= \(\left(\frac{5-3}{4}\right):\frac{17}{20}< \frac{x}{17}< \left(\frac{16}{3}-\frac{7}{2}\right).\frac{12}{17}\)

= \(\frac{1}{2}:\frac{17}{20}< \frac{x}{17}< \left(\frac{32-21}{6}\right).\frac{12}{17}\)

= \(\frac{10}{17}< \frac{x}{17}< \frac{3}{2}.\frac{12}{17}\)

= \(\frac{10}{17}< \frac{x}{17}< \frac{18}{17}\)

( Mik thấy mẫu giống nhau mik sẽ bỏ mẫu đi mik sẽ tìm tử )

=> 10 < 11 ; 12 ; 13 ; 14 ; 15 ; 16 ; 17 < 18

=> x = { 11 ; 12 ; 13 ; 14 ; 15 ; 16 ; 17 }

k mik nha làm ơn đó

Phần c khó để tớ giải cho

Ta có : \(5\frac{8}{17}\div X+\left(-\frac{1}{17}\right)\div X+3\frac{1}{17}\div17\frac{1}{3}=\frac{4}{17}\)

Nên:    \(\left(5\frac{8}{17}+\left(-\frac{1}{17}\right)\right)\div X+\frac{52}{17}\div\frac{52}{3}=\frac{4}{17}\)

           \(5\frac{7}{17}\div X+\frac{52}{17}\times\frac{3}{52}=\frac{4}{17}\)

           \(\frac{92}{17}\div X+\frac{3}{17}=\frac{4}{17}\)

           \(\frac{92}{17}\div X=\frac{4}{17}-\frac{3}{17}\)

           \(\frac{92}{17}\div X=\frac{1}{17}\)

           \(X=\frac{92}{17}\div\frac{1}{17}\)

            \(X=92\)

Vậy \(X=92\)

\(5\frac{8}{17}:x+\left(-\frac{1}{17}\right):x=\frac{52}{51}\)

\(\left(5\frac{8}{17}+-\frac{1}{17}\right):x=\frac{52}{51}\)

\(\frac{92}{17}:x=\frac{52}{51}\)

\(X=\frac{92}{17}:\frac{52}{51}=\frac{69}{13}\)

c) \(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)

\(\Leftrightarrow\left(\frac{x-1}{2009}-1\right)+\left(\frac{x-2}{2008}-1\right)=\left(\frac{x-3}{2007}-1\right)+\left(\frac{x-4}{2006}-1\right)\)

\(\Leftrightarrow\frac{x-2010}{2009}+\frac{x-2010}{2008}-\frac{x-2010}{2007}-\frac{x-2010}{2006}=0\)

\(\Leftrightarrow\left(x-2010\right).\left(\frac{1}{2009}+\frac{1}{2008}-\frac{1}{2007}-\frac{1}{2006}\right)=0\)

\(\Leftrightarrow x-2010=0\)

\(\Leftrightarrow x=0+2010\)

\(\Rightarrow x=2010\)

Vậy \(x=2010.\)

Mình chỉ làm câu c) thôi nhé.

Chúc bạn học tốt!

Tìm x, biết:

3(x+2)(x+5) +5(x+5)(x+10) +7(x+10)(x+17) =x(x+2)(x+17) (x∉−2;−5;−10;−17)

2(x−1)(x−3) +5(x−3)(x−8) +12(x−8)(x−20) −1x−20 =−34 (x∉1;3;8;20)

x+110 +2+111 x+112 =x+113 +x+114 

x−1030 +x−1443 +x−595 +x−1488 =0

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