trả lời hộ mình đi các bạn ai trả lời mình sẽ kết bạn

\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6\)  

\(=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}\) 

\(=\frac{3^{21}}{7^{21}}:\frac{3^{12}}{7^{12}}\) 

\(=\frac{3^{21}}{7^{21}}.\frac{7^{12}}{3^{12}}\) 

\(=\frac{3^9}{7^9}=\left(\frac{3}{7}\right)^9\)

k nha 

a) \(\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}^3\right)^6\)

\(=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{18}\)

\(=\left(\frac{3}{7}\right)^{21-18}\)

\(=\left(\frac{3}{7}\right)^3\)

\(=\frac{27}{343}\)

biết rồi bạn đăng lên làm gì

\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6\)
\(=\left(\frac{3}{7}\right)^{21}:\left(\left(\frac{3}{7}\right)^2\right)^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^{21-12}=\left(\frac{3}{7}\right)^9\)

\(\left(\frac{3}{7}\right)^{21}\div\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}\div\left[\left(\frac{3}{7}\right)^2\right]^6=\left(\frac{3}{7}\right)^{21}\div\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^9\)

= 3- 1+1/4:2

=17/8

\(3-\left(\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2\)

\(=3+1+\frac{1}{4}:2\)

\(=4+\frac{1}{8}\)

\(=\frac{33}{8}\)

Ai cung sai z - - 1 phải = + 1 chứ 

\(=3-1+\frac{1}{2^2.2}\)

\(=2+\frac{1}{8}=\frac{17}{8}\)

= 17 / 8

k cho mk nha

ai k mk mk k lai

 o0oNguyễno0o bn giúp mk nha bài này khó wa

 Harry Potter05 giúp mk đc ko vậy bn!!!

\(\left(\frac{3}{7}\right)^{21}\div\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}\div\left[\left(\frac{3}{7}\right)^2\right]^6=\left(\frac{3}{7}\right)^{21}\div\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^9\)

Bn chỉnh lại đề đi sao lại tiếng anh hả vào toán đi ko được tick đâu

(\(\frac{3}{7}\))²¹ : (\(\frac{9}{49}\))⁶       

  ^{=(\(\frac{3}{7}\))21 : [(\(\frac{3}{7}\))2]6}

   ^{= ( \(\frac{3}{7}\)})^{21 : (\(\frac{3}{7}\))12} 

   ^{= ( \(\frac{3}{7}\)})^{21-12  =} (\(\frac{3}{7}\))⁹ 

\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}:\left(\left(\frac{3}{7}\right)^2\right)^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{2.6}=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}\)

\(=\left(\frac{3}{7}\right)^{21-12}=\left(\frac{3}{7}\right)^9\)