1) \(a=1998^2=1998.1998=1998.\left(1996+2\right)=1998.1996+1998.2\)

\(b=1996.2000=1996.\left(1998+2\right)=1996.1998+1996.2\)

Vì 1998.1996 + 1998.2 > 1996.1998 + 1996.2

=> a > b

\(a=1998^2=1998.1998\)

Ta có :

a = 1998 . 1998

a = 1998 . ( 1996 + 2 )

a = 1998 . 1996 + 1998 . 2

b = 1996 . 2000

b = 1996 . ( 1998 + 2 )

b = 1996 . 1998 + 1996 . 2

Vì 1996 . 2 < 1998 . 2

=> 1998 . 1998 > 1996 . 2000

( 37 . 13 - 13 ) : ( 24 + 37 . 12 )

=  ( 481 - 13 ) : ( 24 + 444 )

= 468 : 468

= 1

\(\left(37.13-13\right):\left(24+37.12\right)\)

 \(=468:468\)

  \(=1\)

\(A=\frac{37\cdot13-13}{24+37\cdot12}=\frac{37\cdot\left(12+1\right)-13}{24+37\cdot12}=\frac{37\cdot12+37-13}{24+37\cdot12}=\frac{37\cdot12+24}{24+37\cdot12}=1\)

BẠN VÔ fx mà ghi

\(A=\frac{37.12+37-13}{24+37.12}\)\(=\frac{37.12+24}{24+37.12}\)\(=1\)

Ai tl đúng và giải chi tiết thì mk tk cho

mk tk cho 3 tk nhé

37.13+13

24+37.12

=13.(37-1)

đăng nhầm

\(\frac{37.13-13}{24+37.12}\)

\(=\frac{37.12+37-13}{24+37.12}\)

\(=\frac{37.12+24}{24+37.12}\)

\(=1\)

= \(\frac{13\left(37-1\right)}{12\left(2+37\right)}=\frac{13.36}{12.39}=1\)

\(\frac{37.13-13}{24+37.12.\left(x-2\right):5}=16\)