125*127*8-25*170*4

=(125*8)*127-(25*4)*170

=1000*127-100*170

=127 000 - 17 000=110 000

a;47.69-31(-41)

=3243-(-1271)

=4514

b,(-14)(-25)+25(-11)

=350+(-275)

=75

c,(-127).57+(-43).127

=(-7239)+(-5461)

=-12700

e,(-25).68+(-34).(-250)

=(-1700)+8500

=6800

f,(-2)^3.(-3)^2

=(-8).9

=-72

 Câu d, cậu ghi ko rõ đề nên tớ ko làm

NHỚ TICK NHA

-(127+38-21)-(121-27+48)+50

=-127-38+21-121+27-48+50

=(-127+27)-(38+48)+(21-121)+50

=-100-86-100+50

=-(100+100+86)+50

=-286+50

=-236

-39+(193-127+96)-(193+196-127)

=-39+193-127+96-193-196+127

=-39+(193-193)-(127+127)+(96-196)

=-39-100

=-139

\(1.125+\left(x-5\right)=130\)

\(\Leftrightarrow125+x+5=130\)

\(\Leftrightarrow x=0\)

\(2.127-\left(5-x\right)=120\)

\(\Leftrightarrow127-5+x=120\)

\(\Leftrightarrow122+x=120\)

\(\Leftrightarrow x=-2\)

\(3.25-\left(x-3\right)=12-x\)

\(\Leftrightarrow25-x+3=12-x\)

\(\Leftrightarrow\left(25-x+3\right)-\left(12-x\right)=0\)

\(\Leftrightarrow25-x+3-12+x=0\)

\(\Leftrightarrow-x+x=-16\)

Vì \(x\in Z\) Nên \(x\) không tồn tại.

\(4.\left(-2\right)^3-\left(x-5\right)=-3+x\)

\(\Leftrightarrow-8-x+5-x=-3\)

\(\Leftrightarrow-2x=-3+8-5\)

\(\Leftrightarrow-2x=0\)

\(\Leftrightarrow x=0\)

\(5.\left(-2\right)^2-\left(6-x\right)=13\)

\(\Leftrightarrow4-6+x=13\)

\(\Leftrightarrow-2+x=12\)

\(\Leftrightarrow x=14\)

1, 125 + (x-5)=130

125+x-5=130

x-5=130-125

x-5=5

x=5+5=10

2, 127-(5-x)=120

127+5+x=120

5+x=120-127

5+x=-7

x=-7-5

x=-12

3, 25-(x-3)=12-x

25+x+3=12-x

28+x=12-x

x+x=12-28

2x=16

x=-8

4, \(\left(-2\right)^3-\left(x-5\right)=-3+x\)

\(\left(-2\right)^3\)+x+5=-3+x

\(\left(-2\right)^3\)+5+(-3)=x+x

-8+5-3=2x

-6=2x

x=-3

5, 3.\(\left(-2\right)^2\)-(6-x)=13

3.(-4)+6+x=13

-12+6+x=13

-6+x=13

x=13+6

x=19

A=-1042

B=-38100

C=9316

D=-50

Bạn làm rõ ra được ko

26: \(x^2-\sqrt{x}+x-1\)

\(=\sqrt{x}\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)+\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)\)

\(=\left(\sqrt{x}-1\right)\left(x\sqrt{x}+x+\sqrt{x}+\sqrt{x}+1\right)\)

\(=\left(\sqrt{x}-1\right)\left(x\sqrt{x}+x+2\sqrt{x}+1\right)\)

25: Ta có: \(-6x+7\sqrt{x}-2\)

\(=-6x+3\sqrt{x}+4\sqrt{x}-2\)

\(=-3\sqrt{x}\left(2\sqrt{x}-1\right)+2\left(2\sqrt{x}-1\right)\)

\(=\left(2\sqrt{x}-1\right)\left(2-3\sqrt{x}\right)\)

27: Ta có: \(2a-5\sqrt{ab}+3b\)

\(=2a-2\sqrt{ab}-3\sqrt{ab}+3b\)

\(=2\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)-3\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)\)

\(=\left(\sqrt{a}-\sqrt{b}\right)\left(2\sqrt{a}-3\sqrt{b}\right)\)

28: Ta có: \(\sqrt{ab}+2\sqrt{a}+3\sqrt{b}+6\)

\(=\sqrt{a}\left(\sqrt{b}+2\right)+3\left(\sqrt{b}+2\right)\)

\(=\left(\sqrt{b}+2\right)\left(\sqrt{a}+3\right)\)

a) ( - 127 ) . 57 + ( - 127 ) . 43

= ( - 127 ) . ( 57 + 43 )

= ( - 127 ) . 100

= - 12 700

b) - 13 . 34 - 8 . 34

=  ( - 13 - 8 ) . 34

= - 21 . 34 = - 714

c) ( - 25 ) . 68 + ( - 34 ) . ( - 250 )

=  ( - 25 ) . 68 + ( - 340 ) . ( - 25 )

= ( - 25 ) . [ 68 + ( - 340 ) ]

= ( - 25 ) . - 272

= 6800

d) Mk ko bt

\(a,\left(-127\right).57+\left(-127\right).43\)

\(=\left(-127\right).\left(57+43\right)\)

\(=\left(-127\right).100\)

\(=-12700\)

\(b,-13.34-87.34\)

\(=34.\left(-13-87\right)\)

\(=34.\left(-100\right)\)

\(=-3400\)

\(c,\left(-25\right).68+\left(-34\right).\left(-250\right)\)

\(=\left(-25\right).68+\left(-34\right).10.\left(-25\right)\)

\(=\left(-25\right).68+\left(-340\right).\left(-25\right)\)

\(=\left(-25\right).\left(68-340\right)\)

\(=\left(-25\right).\left(-272\right)\)

\(=6800\)

1/4 x 127 + 25/100 - 28 x 1/4

= 0,25 x 127 + 0,25 - 28 x 0,25

= 0,25 x (127 + 1 - 28)

= 0,25 x 100

= 25

chúc bn giáng sinh vui vẻ