a, = ((100-2):2+1). (100+2):2= 3050

b, =(99-97)+(95-93)+...+ (7-5)+( 3-1)

= 2+2+2+2+...+2+2

   có ((99-1):2+1):2= 25

= 2.25

=50

B) 99- 97 + 95 – 93 + 91 – 89 + ... + 7 - 5 + 3 -1

= ( 99 - 97 ) + ( 95 – 93) + (91 – 89) + ... + (7 - 5 ) + (3 - 1)

= 2 + 2+ 2 + ...+ 2 + 2 (có 25 số 2)

= 2.25

= 50

Bài 1: 

a) \(\dfrac{65}{91}+\dfrac{-33}{55}=\dfrac{5}{7}+\dfrac{-3}{5}=\dfrac{25}{35}+\dfrac{-21}{35}=\dfrac{4}{35}\)

b) \(\dfrac{36}{-84}+\dfrac{100}{450}=\dfrac{-3}{7}+\dfrac{2}{9}=\dfrac{-27}{63}+\dfrac{14}{63}=\dfrac{-13}{63}\)

\(A=\dfrac{5}{11}.\dfrac{5}{7}+\dfrac{5}{11}.\dfrac{2}{7}+\dfrac{6}{11}=\dfrac{5}{11}\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\dfrac{6}{11}=\dfrac{5}{11}.1+\dfrac{6}{11}=\dfrac{5}{11}+\dfrac{6}{11}=\dfrac{11}{11}=1\)

\(B=\dfrac{3}{13}.\dfrac{6}{11}+\dfrac{3}{13}.\dfrac{9}{11}-\dfrac{3}{13}.\dfrac{4}{11}=\dfrac{3}{13}\left(\dfrac{6}{11}+\dfrac{9}{11}-\dfrac{4}{11}\right)=\dfrac{3}{13}.1=\dfrac{3}{13}\)

\(C=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right)\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right).0=0\)

a,

Đặt A=99-97+95-93+91-89+...+7-5+3-1

A={99-97}+{95-93}+{91-89}+...+{3-1}

A=2        +   2     +    2     +...+   2        có 25 chữ số 2

A=2.25

A=50

Đúng 100/100 luôn đó cho minh nhá

a) Ta có: 99-97+95-93+91-89+...+7-5+3-1=

=(99-97)+(95-93)+(91-89)+...+(7-5)+(3-1)=

= 2+2+2+...+2+2 (25 số 2)=2.25=50

a) 99 - 97 + 95 - 93 + 91 - 89 +.....+ 7 - 5 + 3 - 1

= (99 - 97) + (95 - 93) + (91 - 89) +.... + (7 - 5) + ( 3 - 1)

= 2 + 2 + .... + 2

= 2 x 25 = 50

Vậy giá trị biểu thức là 50

b) 50 - 49 + 48 - 47 + 46 - 45 + ..... + 4 - 3 + 2 - 1

= (50 - 49) + (48 - 47) +......+(4 - 3) + (2 - 1)

= 1 + 1 +.....+ 1 + 1

= 1 x 25 = 25

Vậy giá trị biểu thức là 25