5 x 217 x 20 - 4 x 215 x 25 

= 1085 x 20 - 4 x 215 x 25

= 21700 - 4 x 215 x 25

= 21700 - 860 x 25

= 21700 - 21500

= 200

\(5.217.20-4.215.25\)

\(=\left(5.20\right).217-\left(4.25\right).215\)

\(=100.217-100.215\)

\(=100.\left(217-215\right)\)

\(=100.2=200\)

Nhớ k cho mình nhé! thank you!!!

Bài 1 :

Gọi \(A=5+5^2+5^3+...+5^{98}+5^{99}\\ 5A=5^2+5^3+5^4+...+5^{99}+5^{100}\\ 5A-A=\left(5^2+5^3+5^4+...+5^{99}+5^{100}\right)-\left(5+5^2+5^3+...+5^{98}+5^{99}\right)\\ 4A=5^{100}-5\\ A=\dfrac{5^{100}-5}{4}\)

Bài 2:

\(\left(12x-4\right)\cdot8^{2022}=4\cdot8^{2023}\\ 12x-4=4\cdot8^{2023}:8^{2022}\\ 12x-4=4\cdot8\\ 12x-4=32\\ 12x=36\\ x=3\)

    57 \(\times\) 46 + 57 \(\times\) 54

= 57    \(\times\) ( 46 + 54)

= 57 \(\times\) 100

= 5700

137 + 355 + 63 + 45

= ( 137 + 63) + ( 355 + 45)

= 200 + 400

= 600

215 \(\times\) 48 - 215 \(\times\) 38

= 215 \(\times\) ( 48 - 38)

= 215 \(\times\) 10

= 2150 

4 \(\times\) 50 \(\times\) 25 

= ( 4 \(\times\) 25) \(\times\) 50

= 100 \(\times\) 50

= 5 000

57×(46+54) =57×100=5700

137+355+63+45=(137+63) +(355+45) =200+400=600

215×48-215×38=215×(48-38) =215×10=2150

4×50×25=(4×25) ×50=100×50=5000

\(\frac{217-x}{207}+\frac{215-x}{209}+\frac{213-x}{211}+\frac{211-x}{213}+4=0\)

\(\Leftrightarrow\)\(\left(\frac{217-x}{207}+1\right)+\left(\frac{215-x}{209}+1\right)+\left(\frac{213-x}{211}+1\right)+\left(\frac{211-x}{213}+1\right)=0\)

\(\Leftrightarrow\)\(\frac{424-x}{207}+\frac{424-x}{209}+\frac{424-x}{211}+\frac{424-x}{213}=0\)

\(\Leftrightarrow\)\(\left(424-x\right)\left(\frac{1}{207}+\frac{1}{209}+\frac{1}{211}+\frac{1}{213}\right)=0\)

\(\Leftrightarrow\)\(424-x=0\)   (do 1/207 + 1/209 + 1/211 + 1/213 # 0)

\(\Leftrightarrow\)\(x=424\)

Vậy...

câu này sao ko có ai trả lời nhỉ

Đặt \(A=\frac{1.2+2.4+3.6+4.8+5.10}{4+6.8+9.12+12.16+15.20}\)

\(\Rightarrow A=\frac{1.\left(1+2\right)+2.\left(1+2\right)+3.\left(1+2\right)+4.\left(1+2\right)+5.\left(1+2\right)}{4+2.\left(3+4\right)+3.\left(3+4\right)+4.\left(3+4\right)+5.\left(3+4\right)}\)

\(\Rightarrow A=\frac{\left(1+2+3+4+5\right).\left(1+2\right)}{4+\left(2+3+4+5\right).\left(3+4\right)}\)

\(\Rightarrow A=\frac{\left(1+5\right).5:2.\left(1+2\right)}{4+\left(2+5\right).4:2.\left(3+4\right)}\)

\(\Rightarrow A=\frac{6.5:2.3}{4+7.4:2.7}=\frac{45}{4+98}=\frac{45}{102}=\frac{15}{34}\)

Vậy \(A=\frac{15}{34}\)

Chúc bn học tốt

44099

ủng hộ mk nha các bạn

sắp sang năm mới mọi người ủng hộ vài đi

Ta có: x=100

nên x+1=101

Ta có: \(f\left(x\right)=x^8-101x^7+101x^6-101x^5+...+101x^2-101x+25\)

\(=x^8-x^7\left(x+1\right)+x^6\left(x+1\right)-x^5\left(x+1\right)+...+x^2\left(x+1\right)-x\left(x+1\right)+25\)

\(=x^8-x^7-x^7+x^7+x^6-x^6-x^5+x^5-x^4+...+x^3+x^2-x^2-x+25\)

\(=-x+25\)

\(=-100+25=-75\)

hơi khó hỉu