a) Ta có: \(\frac{2\cdot\left(-13\right)\cdot9\cdot10}{\left(-3\right)\cdot4\cdot\left(-5\right)\cdot26}=\)\(\frac{2\cdot\left(-1\right)\cdot13\cdot3\cdot3\cdot2\cdot5}{3\cdot\left(-1\right)2\cdot2\cdot\left(-1\right)\cdot5\cdot2\cdot13}\)=\(-3.\)

b)Ta có: \(\frac{15\cdot8+15\cdot4}{12\cdot3}=\frac{15\left(8+4\right)}{12\cdot3}\)=\(\frac{15\cdot12}{12\cdot3}=\frac{15}{3}=5\)

a) \(\frac{2.\left(-13\right).9.10}{\left(-3\right).4.\left(-5\right).26}=\frac{18.\left(-130\right)}{\left(-12\right).\left(-130\right)}=\frac{-3}{2}\)

b) \(\frac{15.8+15.4}{12.3}=\frac{15.\left(8+4\right)}{12.3}=\frac{15.12}{12.3}=5\)

a) Ta có: \(\frac{2.\left(-13\right).9.10}{\left(-3\right).4.\left(-5\right).26}=\frac{2.\left(-13\right).3^2.2.5}{3.2^2.5.2.13}\)

                                                \(=\frac{\left(-13\right).2^2.3^2.5}{2^3.3.5.13}\)

                                                 \(=-\frac{3}{2}\)

b) Ta có: \(\frac{15.8+15.4}{12.3}=\frac{3.5.\left(8+4\right)}{2^2.3.3}\)

                                         \(=\frac{3.5.2^2.3}{2^2.3.3}\)

                                         \(=5\)

a, Ta có cách làm sau

\(\dfrac{15.8+15.4}{12.3}=\dfrac{15.\left(8+4\right)}{12.3}=\dfrac{15.12}{12.3}=\dfrac{3.5.12}{12.3}\)

\(=\dfrac{5}{1}=5\)

b,

\(\dfrac{2.\left(-13\right).9.10}{-3.4.\left(-5\right).26}\)=\(\dfrac{2.\left(-13\right).\left(-3\right).\left(-3\right).\left(-2\right).\left(-5\right)}{-3.2.2_{ }.\left(-5\right).\left(-2\right).\left(-13\right)}\)=\(\dfrac{-3}{2}\)

\(\frac{15.8+15.4}{12.3}\)

\(=\frac{15.\left(8+4\right)}{12.3}\)

\(=\frac{15.12}{12.3}\)

\(=5\)

~Study well~

#KSJ

trả lời ;

\(\frac{15.8+15.4}{12.3}\)

=\(\frac{15.\left(8+4\right)}{12.3}\)

=\(\frac{15.12}{12.3}\)

=5

Em chx học nhưng, mong cj học tốt ạ !

\(\frac{15\cdot8+15\cdot4}{12\cdot3}=\frac{15\left(8+4\right)}{12\cdot3}=\frac{15\cdot12}{12\cdot3}=5\)

Vậy : \(\frac{15\cdot8+15\cdot4}{12\cdot3}=5\)

bằng 1 hihihihi

băng 1 haha

15.8+15.4/12.3 = 17.0520325203

\(\frac{15.8+15.4}{12.3}=\frac{15.\left(8+4\right)}{12.3}=\frac{15.12}{12.3}=5\)

\(\frac{15.8+15.4}{12.3}=\frac{15.\left(8+4\right)}{12.3}=\frac{15.12}{12.3}=\frac{5}{1}=5\)

\(\frac{15.8+15.4}{12.3}=\frac{15.\left(8+4\right)}{12.3}=\frac{5.12}{4.3}=\frac{5}{1}=5\)

a. -1100/9

b. -3452/11