Ta có : S = 1.2 + 2.3 + 3.4 + ..... + 32.33

=> 3S = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ...... + 32.33.34

=> 3S = 32.33.34

=> S = \(\frac{32.33.34}{3}=11968\)

​A rê. Lớp 6 ngược mà hỏi bài đó hở

đây là bài của bảo trân

Lời giải :

Đặt S=1.2+2.3+3.4+4.5+…+99.100+100.101

3S=1.2.3+2.3.3+3.4.3+4.5.3+…+99.100.3+100.101.3

=1.2(3−0)+2.3(4−1)+3.4(5−2)+4.5(6−3)+…+99.100(101−98)+100.101(102−99)

=0.1.2-1.2.3+1.2.3-2.3.4+...+99.100.101-100.101.102

=100.101.102

S=100.101.34=343400

1.Tính 

a) Ta có: 

  A=(1-1/2²).(1-1/3²)...(1-1/100²)

=>A=3/2².8/3².....9999/100²

=>A=(1.3/2.2).(2.4/3.3).....(99.101/100.100)

=>A=(1.2.3.....99/2.3.4.....100).(3.4.5.....101/2.3.4.....100)

=>A=1/100.101/2

=>A=101/200

b) Ta có: 

  B=-1/1.2-1/2.3-1/3.4-...-1/100.101

=>B=-(1/1.2+1/2.3+1/3.4+...+1/100.101)

=>B=-(1-1/2+1/2-1/3+1/3-1/4+...+1/100-1/101)

=>B=-(1-1/101)

=>B=-100/101

 c) Ta có:

 C=1.2+2.3+3.4+...+100.101

       =>3C=1.2.3+2.3.3+3.4.3+...+100.101.3

       =>3C=1.2.3+2.3.(4-1)+3.4.(5-2)+...+100.101.(102-99)

       =>3C=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-3.4.5+...+100.101.102

       =>3C=100.101.102

       =>3C=1030200

       =>C=343400

Chúc bạn hok tốt nhé >:)!!!!!

A x 3 = 1.2.3 + 2.3.3 + ...+ 19.20.3

A x 3 = 1.2.( 3 - 1) + 2.3.(4 - 1) + ...+ 19.20.( 21-18)

A x 3 = ( 1.2.3 + 2.3.4 + ....+ 19.20.21) - ( 0.1.2 + 1.2.3 + ....+ 18.19.20)

=> A x 3 =  19 x 20 x 21 = 7890 

\(3A=1.2.3+2.3.3+....+19.20.3\)

\(3A=1.2.\left(3-0\right)+2.3.\left(4-1\right)+....+19.20\left(21-18\right)\)

\(3A=1.2.3-1.2.0+2.3.4-2.3.1+....+19.20.21-19.20.18\)

ta có thể thấy 1.2.3 = 2.3.1 và những con số khác cũng vậy

\(\Rightarrow3A=19.20.21\)

mink nghĩ vậy bạn ạ, sai đừng trách mink nha

D = 1.2 + 2.3+ 3.4 +...+ 99.100

=>3D=1.2.3+2.3.3+3.4.3+...+99.100.3

=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+....+99.100.(101-98)

=1.2.3-0.1.2+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100

=99.100.101-0.1.2

=99.100.101

=999900

=>D=999900:3=333300

Dn = 1.2 + 2.3 + 3.4 +...+ n (n +1)

=>3Dn=1.2.3+2.3.3+3.4.3+...+n(n+1).3

=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+...+n.(n+1).[(n+2)-(n-1)]

=1.2.3-0.1.2+2.3.4-1.2.3+2.3.4-2.3.4+....+n(n+1)(n+2)-(n-1)n(n+1)

=n.(n+1).(n+2)-0.1.2

=n.(n+1)(n+2)

=>Dn=n.(n+1)(n+2):3

 =>điều cần chứng minh

A=3/1.2+3/2.3+3/3.4+3/4.5+...+3/2021.2022

A=3(1/1.2+1/2.3+1/3.4+1/4.5+...+1/2021.2022)

A=3(1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/2021-1/2022)

A=3[1/1+(1/2-1/2)+(1/3-1/3)+(1/4-1/4)+...+(1/2021-1/2021)-1/2022]

A=3[1/1+0+0+0+...+0-1/2022

A=3(1/1-1/2022)

A=3(2022/2022-1/2022)

A=3.2021/2022

A=2021/674

Bn Tham Khảo:

https://hoc247.net/hoi-dap/toan-6/tinh-tong-s-3-1-2-3-2-3-3-3-4-3-4-5-3-2015-2016-faq188428.html

3S=1*2*3+2*3*(4-1)+...+99*100*(101-98)

=1*2*3+2*3*4-1*2*3+...+99*100*101-99*100*98

=99*100*101

=>S=33*100*101=333300

đây là A= chứ có phải S= đou bạn:)))