\(\overline{abc,de1}=0,3x\overline{1abc,de}\)

\(\Rightarrow\overline{abc,de1}=\frac{3x\overline{1abc,de}}{10}\Rightarrow\overline{abcd,e1}=3x\overline{1abc,de}\)

\(\Rightarrow\overline{abcde1}=3x\overline{1abcde}\)

\(\Rightarrow10x\overline{abcde}+1=300000+3x\overline{abcde}\)

\(\Rightarrow7x\overline{abcde}=299999\Rightarrow\overline{abcde}=42857\)

\(\Rightarrow\overline{abc,de1}=428,571\)

k nha đúng pls

Đáp án:

Giải thích các bước giải: a7b,8c9:10.01=ac,b

a7b,8c9=ac,b*10,01

a7b,8c9 =ac,b*(10+0,01)

a7b,8c9=acb,acb

suy ra: a=8, b=9, c=7

Cám ơn 4

a7b,8c9 : 10,01=ac,b

a7b,8c9=ac,b×10.01

a7b,8c9=ac,b×(10+0,01)

a7b,8c9=acb,acb

Suy ra a=8;b=9;c=7(cau 1)

a7b,8c9 : 10,01=ac,b

a7b,8c9=ac,b×10.01

a7b,8c9=ac,b×(10+0,01)

a7b,8c9=acb,acb

Suy ra a=8;b=9;c=7(cau 1)

1abc,de . 0,3= abc,de1

=>1abc,de . 0,3. 1000=abc,de1

=>1abc,de.0,3.1000=abc,de1.1000

1abcde.3=abcde1

Đặt abcde=X

Ta có (100000+X).3=X1

300000+3X=10X+1

299999=7X

X=42857

abc,de=428,57

dễ như ăn cháo

\(\overline{abc,de1}=0,3.\overline{1abc,de}\)

\(\overline{abc,de1}=\dfrac{3.\overline{1abc,de}}{10}\)

\(\overline{abcde1}=3.\overline{1abcd}\)

\(10.\overline{abcde}+1=300000+3.\overline{abcde}\)

\(7.\overline{abcde}=299999\)

\(\overline{abc,de1}=428,571\)

Vậy a = 4 ; b = 2; c= 8 ; d= 5; e=7

1abc,de *0,3=abc,de1

1abc,de x 100 x 0,3 x 10 = abc,de1 x 1000

1abcde x 3 = abcde1

(100000 + abcde) x 3 = abcde x 10 + 1

300000 + abcde x 3 = abcde x 10 + 1

abcde x 10 - abcde x 3 = 300000 - 1

abcde x 7 = 299999

abcde = 299999 : 7

abcde = 42857

Vậy a = 4; b = 2; c = 8; d = 5; e = 7

1abc,de x 100 x 0,3 x 10 = abc,de1 x 1000

1abcde x 3 = abcde1

(100000 + abcde) x 3 = abcde x 10 + 1

300000 + abcde x 3 = abcde x 10 + 1

abcde x 10 - abcde x 3 = 300000 - 1

abcde x 7 = 299999

abcde = 299999 : 7

abcde = 42857

Vậy a = 4; b = 2; c = 8; d = 5; e = 7