thuc hien phep tinh A=1/(a-b)(a-c)+1/(b-a)(b-c)+1/(c-a)(c-b)
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a: A=120-61x(-8)
=120+488=608
b: =47(-136+36)-(-1)
=-4700+1=-4699
c: C=(-48-304+72)+36
=-352+72+36
=-280+36=-244
a,3/7 +1/2-[-3]/70
=13/14 -[-3]/70
=65/70 -[-3]/70
=34/35
b,3/5+-1/25 -35/100
=14/25 - 35/100
=56 /100 -35/100
= 21/100
c ,5/12 -3/-16+3/4
=29/48 +3/4
= 29/48 +36/48
=65/48
d, 5/15 +4/-12 +1/7 -1/-6
= 1/3 +1/-3 +1/7-1/-6
=0+1/7-1/-6
= 13/42
A.\(\dfrac{3}{7}+\dfrac{1}{2}+\dfrac{\left(-3\right)}{70}\)
=\([\dfrac{30}{70}+\dfrac{\left(-3\right)}{70}]\)+\(\dfrac{1}{2}\)
= \(\dfrac{27}{70}+\dfrac{35}{70}\)
=\(\dfrac{62}{70}=\dfrac{31}{35}\)
B.\(\dfrac{3}{5}+\dfrac{-1}{25}-\dfrac{35}{100}\)
=\(\dfrac{60}{100}+\dfrac{-4}{100}-\dfrac{35}{100}\)
=\(\dfrac{60+\left(-4\right)-35}{100}\)
=\(\dfrac{21}{100}\)
C.\(\dfrac{5}{12}-\dfrac{3}{-16}+\dfrac{3}{4}\)
=\(\left(\dfrac{5}{12}+\dfrac{9}{12}\right)-\dfrac{-3}{16}\)
=\(\dfrac{7}{6}-\dfrac{-3}{16}\)
=\(\dfrac{56}{48}-\dfrac{-9}{48}\)=\(\dfrac{65}{48}\)
D.\(\dfrac{5}{15}+\dfrac{4}{-12}+\dfrac{1}{7}-\dfrac{1}{-6}\)
=\(\dfrac{1}{3}+\dfrac{1}{7}+(\dfrac{-2}{6}-\dfrac{-1}{6})\)
=\(\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{-1}{6}\)
=\((\dfrac{1}{3}+\dfrac{-1}{6})+\dfrac{1}{7}\)
=\(\dfrac{1}{6}+\dfrac{1}{7}\)=\(\dfrac{13}{42}\)
Giải:
a) \(\left(x^2+2x+1\right)\left(x+1\right)\)
\(=x^2.x+2x.x+1.x+x^2.1+2x.1+1.1\)
\(=x^3+2x^2+x+x^2+2x+1\)
\(=x^3+3x^2+3x+1\)
b) \(\left(x^3-x^2+2x-1\right)\left(5-x\right)\)
\(=x^3.5-x^2.5+2x.5-1.5+x^3.\left(-x\right)-x^2.\left(-x\right)+2x.\left(-x\right)-1.\left(-x\right)\)
\(=5x^3-5x^2+10x-5-x^4+x^3-2x^2+x\)
\(=6x^3-7x^2+11x-5-x^4\)
c) \(\left(x-5\right)\left(x^3-x^2+2x-1\right)\)
\(=x.x^3-5.x^3+x.\left(-x^2\right)-5.\left(-x^2\right)+x.2x-5.2x+x.\left(-1\right)-5.\left(-1\right)\)
\(=x^4-5x^3-x^3+5x^2+2x^2-10x-x+5\)
\(=x^4-6x^3+7x^2-11x+5\)
Chúc bạn học tốt!!!
lớp 8 Phạm Hoàng Giang không chơi kiểu lớp 7
đúng làm 8 mà làm
\(A=\left(x^2+2x+1\right)\left(x+1\right)=\left(x+1\right)^2\left(x+1\right)=\left(x+1\right)^3\)
\(A=x^3+3x^2+3x+1\)
a, 516 x 2,15 = 1109,4
b, 2,1655 : 5 = 0,4331
c, \(\frac{15}{4}\)x \(\frac{8}{3}\)x \(\frac{16}{25}\)x \(\frac{1}{5}\)
= 10 x \(\frac{16}{25}x\frac{1}{5}\)
= \(\frac{32}{5}x\frac{1}{5}\)
= \(\frac{32}{25}\)
d, \(\frac{3}{7}:\frac{5}{4}x\frac{3}{5}\)
= \(\frac{3}{7}x\frac{4}{5}x\frac{3}{5}\)
= \(\frac{12}{35}x\frac{3}{5}\)
= \(\frac{36}{175}\)
cậu lấy máy tính ra mà tính toán này của sách tập 1 số nguyên đúng không