\(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+\frac{3}{130}+....+\frac{3}{418}+\frac{3}{550}\)

\(\Leftrightarrow\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+...+\frac{3}{19.22}+\frac{3}{22.25}\)

\(\Leftrightarrow\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{19}-\frac{1}{22}+\frac{1}{22}-\frac{1}{25}\)

\(\Leftrightarrow\frac{1}{1}-\frac{1}{25}=\frac{24}{25}\)

Nhớ k cho m nhé!

= \(\frac{9}{1x4}+\frac{9}{4x7}+\frac{9}{7x10}+.........+\frac{9}{19x22}+\frac{9}{22x25}\)

= \(\frac{1}{3}x\left(\frac{9}{1}-\frac{9}{4}\right)+\left(\frac{9}{4}-\frac{9}{7}\right)x\frac{1}{3}+........+\left(\frac{9}{22}-\frac{9}{25}\right)x\frac{1}{3}\)

= \(\frac{1}{3}\left(\frac{9}{1}-\frac{9}{4}+\frac{9}{4}-\frac{9}{7}+....+\frac{9}{22}-\frac{9}{25}\right)\)

= \(\frac{1}{3}x\left(\frac{9}{1}-\frac{9}{25}\right)\)

= \(\frac{1}{3}x\frac{216}{25}\)

= \(\frac{72}{25}\)

nhớ ********** nha bn thân

\(\frac{9}{4}+\frac{9}{28}+\frac{9}{70}+\frac{9}{130}+...+\frac{9}{418}+\frac{9}{550}\)

\(=3\left(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{19.22}+\frac{3}{22.25}\right)\)

\(=3\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{22}-\frac{1}{25}\right)\)

\(=3\left(1-\frac{1}{25}\right)\)

\(=3.\frac{24}{25}=\frac{72}{25}\)

\(C=\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{997.999}\)

\(\Leftrightarrow C=\frac{5}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{997.999}\right)\)

\(\Leftrightarrow C=\frac{5}{2}\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{997}-\frac{1}{999}\right)\)

\(\Leftrightarrow C=\frac{5}{2}\left(1-\frac{1}{999}\right)=\frac{5}{2}.\frac{998}{999}=\frac{2495}{999}=2\frac{497}{999}\)

\(A=\frac{2}{4}+\frac{2}{28}+\frac{2}{70}+\frac{2}{130}+\frac{2}{208}\)

\(\Leftrightarrow A=\frac{2}{1.4}+\frac{2}{4.7}+\frac{2}{7.10}+\frac{2}{10.13}+\frac{2}{13.16}\)

\(\Leftrightarrow A=\frac{2}{3}\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+\frac{3}{13.16}\right)\)

\(\Leftrightarrow A=\frac{2}{3}\left(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\frac{1}{16}\right)\)

\(\Leftrightarrow A=\frac{2}{3}\left(1-\frac{1}{16}\right)=\frac{2}{3}.\frac{15}{16}=\frac{5}{8}\)

C = 5/1x3 + 5/3x5 + 5/5x7 + ... + 5/997x999

C = 5 - 5/3 + 5/3 - 5/5 + 5/5 - 5/7 + ... + 5/997 - 5/999

C = 5 - 5/999

C = bạn tự tính nhé !

A = 2/4 + 2/28 + 2/70 + 2/130 + 2/208

A = 2/1x4 + 2/4x7 + 2/7x10 + 2/10x13 + 2/13x16

A = 2 - 2/4 + 2/4 - 2/7 + 2/7 - 2/10 + 2/10 - 2/13 + 2/13 - 2/16

A = 2 - 2/16

A = bạn tự tính nhé !

Đặt A = 9/4  + 9/28 +.. + 9/550

       A = 9/1.4 + 9/4.7 +... + 9/22.25

       A = 3( 3/1.4 + 3/4.7 + .. + 3/22.25)

        A  = 3 . (1/1 - 1/4 + 1/4  - 1/7 + ... +1/22 - 1/25)

         A = 3 (1 - 1/25)

       A   = 3. 24 / 25

       A   =  72/25

2. \(\frac{11}{5}-\frac{3}{5}\times\left(2-\frac{3}{2}\right)\)

\(=\frac{11}{5}-\left(\frac{3}{5}\times2-\frac{3}{5}\times\frac{3}{2}\right)\)

\(=\frac{11}{5}-\left(\frac{6}{5}-\frac{9}{10}\right)=\frac{11}{5}-\frac{3}{10}=\frac{22}{10}-\frac{3}{10}=\frac{19}{10}\)

3.\(\frac{19}{32}\times\frac{17}{21}+\frac{17}{21}:\frac{32}{13}=\frac{19}{32}\times\frac{17}{21}+\frac{17}{21}\times\frac{13}{32}\)

\(=\frac{17}{21}\times\left(\frac{19}{32}+\frac{13}{32}\right)=\frac{17}{21}\times1=\frac{17}{21}\)

4. \(19,26\times81+192,6\times1,8+19,26\)

\(=19,26\times81+\left[\left(192,6:10\right)\times\left(1.8\times10\right)\right]+19,26\times1\)

\(=19,26\times81+19,26\times18+19,26\times1\)

\(=19,26\times\left(81+18+1\right)=19,26\times100=1926\)

CÂU 1 VÀ CÂU 5 KO BIK LÀM MONG BN THÔNG CẢM

câu 1 : Msc : 90 KQ :  1/8

câu 2 : chưa ra nha xin lỗi 

câu 3 : chép nguyên phần đầu chuyển chia 32/13 thành * 13/32 * 1 làm như bt kq : 17/21

câu 4 : chép từ đầu đến 192 , 6 thành 19,26 rồi trả 10 thành 18 làm như bt kq : 1926

câu 5 : tách ra dài lắm nhưng bạn biết làm rồi mà 

( mình là chủ nick kia , câu hỏi đáp này nè ) 

Lướt qua rồi! không phải bạn k mà ấn tượng "đừng lướt qua"

\(A=\frac{3a}{4.1}+\frac{3a}{7.4}+\frac{3a}{10.7}+\frac{3a}{13.10}+..+\frac{3a}{22.19}+\frac{3a}{25.22}=\frac{48}{25}\)

\(a.\left(\frac{3}{4.1}+\frac{3}{7.4}+\frac{3}{10.7}+\frac{3}{13.10}+..+\frac{3}{22.19}+\frac{3}{25.22}\right)=\frac{48}{25}\)

\(B=\left(\frac{3}{4.1}+\frac{3}{7.4}+\frac{3}{10.7}+\frac{3}{13.10}+..+\frac{3}{22.19}+\frac{3}{25.22}\right)\)

\(B=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+..+\frac{1}{22}-\frac{1}{25}\)

\(B=\frac{1}{1}-\frac{1}{25}=\frac{24}{25}\)

\(A=a.B=\frac{24a}{25}=\frac{48}{25}\Rightarrow a=2\)

\(\frac{3a}{4}+\frac{3a}{28}+\frac{3a}{70}+...+\frac{3a}{418}+\frac{3a}{550}=\frac{48}{25}\)

\(\Rightarrow a\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{19.22}+\frac{3}{22.25}\right)=\frac{48}{25}\)

\(\Rightarrow a\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{19}-\frac{1}{22}+\frac{1}{22}-\frac{1}{25}\right)=\frac{48}{25}\)

\(\Rightarrow a\left(1-\frac{1}{25}\right)=\frac{48}{25}\)

\(\Rightarrow a.\frac{24}{25}=\frac{48}{25}\)

\(\Rightarrow a=2\)