\(7.7^{x+1}=343\)

\(\Rightarrow7.7^{x+1}=7^3\)

\(\Rightarrow7^{x+1}=7^3:7\)

\(\Rightarrow7^{x+1}=7^2\)

\(\Rightarrow x+1=2\)

\(\Rightarrow x=2-1=1\)

Ai đó hãy giúp giải bà này đi 

Chọn A

e tách ra nhé.☘

;))

a.(3^2+4^2).x=10^2

(9+16).x     =100

25.x           =100

x                =100:25

x                =4

b.(x-5)^2       =81

x-5             =9

x                =9+5

x                =14

c.(2x+1)^3 = 343

2x+1          = 7

2x              =7-1

2x              =6

x                =6:2

x                = 3

(9+16).x=100

25.x=100

x=100:25

x=4

Trả lời:

a, 3⁵:3³= 3²

b, 125= 5³

125:5³= 5³:5³= 5¹= 5

d, a¹²: a⁸= a⁴

Chúc bn học tốt

Chỉ cacahs làm luôn nha

\(a,\left(\frac{1}{2}\right)^M=\frac{1}{32}\)

\(\Leftrightarrow\left(\frac{1}{2}\right)^M=\left(\frac{1}{2}\right)^5\)

\(\Leftrightarrow M=5\)

\(b,\frac{343}{125}=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow n=3\)

a) Ta có: \(\left(\frac{1}{2}\right)^m=\frac{1}{32}\)

Mà \(\frac{1}{32}=\left(\frac{1}{2}\right)^5\)

\(\Rightarrow\left(\frac{1}{2}\right)^m=\left(\frac{1}{2}\right)^5\Rightarrow m=5\)

b)Ta có:  \(\frac{343}{125}=\left(\frac{7}{5}\right)^3\)

Mà \(\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\Rightarrow n=3\)

\(a)\) \(\left(\frac{1}{2}\right)^m=\frac{1}{32}\)

\(\Leftrightarrow\)\(\left(\frac{1}{2}\right)^m=\frac{1^5}{2^5}\)

\(\Leftrightarrow\)\(\left(\frac{1}{2}\right)^m=\left(\frac{1}{2}\right)^5\)

\(\Leftrightarrow\)\(m=5\)

Vậy \(m=5\)

\(b)\) \(\frac{343}{125}=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow\)\(\frac{7^3}{5^3}=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow\)\(\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\)

\(\Leftrightarrow\)\(n=3\)

Vậy \(n=3\)

Chúc bạn học tốt ~