\(\left(\frac{3}{4}x-\frac{9}{16}\right)\cdot\left(1,5+\frac{-3}{5}:x\right)=0\\ \Rightarrow\left[{}\begin{matrix}\frac{3}{4}x-\frac{9}{16}=0\\1,5+\frac{-3}{5}:x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}\frac{3}{4}x=\frac{9}{16}\\\frac{-3}{5}:x=-1,5\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\frac{3}{4}\\x=\frac{2}{5}\end{matrix}\right.\)

Vậy \(x\in\left\{\frac{3}{4};\frac{2}{5}\right\}\)

\(\left(\frac{9}{16}\right)^{2016}.\left(\frac{16}{9}\right)^{2015}.\frac{4}{3}\)

=\(\left(\frac{3}{4}\right)^{4032}.\left(\frac{4}{3}\right)^{4030}.\frac{4}{3}\)

=

\(\left(\frac{9}{16}\right)^{2016}.\left(\frac{16}{9}\right)^{2015}.\frac{4}{3}=\left(\frac{9}{16}\right)^{2016}:\left(\frac{9}{16}\right)^{2015}.\frac{4}{3}\)

                                                     \(=\frac{9}{16}.\frac{4}{3}\)

                                                         \(=\frac{3}{4}\)

\(\left(\frac{9}{16}\right)^{2016}\cdot\left(\frac{16}{9}\right)^{2015}\cdot\frac{4}{3}=\left(\frac{9}{16}\right)^{2016}\cdot\left(\frac{9}{16}\right)^{2015}\cdot\frac{4}{3}\)

                                                 \(=\frac{9}{16}\cdot\frac{4}{3}\)

                                                 \(=\frac{3}{4}\)

=\(\frac{9^{2016}}{16^{2016}}.\frac{16^{2015}}{9^{2015}}.\frac{4}{3}\)

=\(\frac{9}{16}.\frac{4}{3}\)

=\(\frac{3}{4}\)

k cho mk nhoa

\(\left(\frac{9}{16}\right)^{2016}.\left(\frac{16}{9}\right)^{2015}.\frac{4}{3}\)

\(=\left[\frac{9}{16}\left(\frac{9}{16}\right)^{2015}\right].\left(\frac{16}{9}\right)^{2015}.\frac{4}{3}\)

\(=\frac{9}{16}\left[\left(\frac{9}{16}\right)^{2015}.\left(\frac{16}{9}\right)^{2015}\right].\frac{4}{3}\)

\(=\frac{9}{16}\left[\left(\frac{9}{16}.\frac{16}{9}\right)^{2015}\right].\frac{4}{3}\)

\(=\frac{9}{16}.1^{2015}.\frac{4}{3}\)

\(=\frac{9}{16}.\frac{4}{3}\)

\(=\frac{3}{4}\)

tính giá trị biểu thức chứ còn cái gì nữa

a, \(A=\frac{22}{27}\)

b,\(B=\frac{1}{57}\)

C,\(C=\frac{1}{50}\)

d, \(D=0\)

\(\left(1-\frac{1}{4}\right)\times\left(1-\frac{1}{9}\right)\times...\times\left(1-\frac{1}{625}\right)\)

\(=\frac{3}{4}\times\frac{8}{9}\times...\times\frac{623}{624}\)

\(=\frac{1\times3}{2\times2}\times\frac{2\times4}{3\times3}\times...\times\frac{24\times26}{25\times25}\)

\(=\frac{1\times3\times2\times4\times...\times24\times26}{2\times2\times3\times3\times...\times25\times25}\)

Từ đây mình viết nhân là chấm nha mong bạn thông cảm :

\(=\frac{\left(1\cdot2\cdot3\cdot...\cdot24\right)\cdot\left(3\cdot4\cdot5\cdot...\cdot26\right)}{\left(2\cdot3\cdot4\cdot...\cdot25\right)\cdot\left(2\cdot3\cdot4\cdot...\cdot25\right)}\)

\(=\frac{1\cdot26}{25\cdot2}\)

\(=\frac{26}{50}=\frac{13}{25}\)

k tớ nha

\(T=(1-\frac{1}{4}).(1-\frac{1}{9}).(1-\frac{1}{16}).....(1-\frac{1}{576}).(1-\frac{1}{625})\)

\(T=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}....\frac{575}{576}.\frac{624}{625}\)

\(T=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}...\frac{23.25}{24.24}.\frac{24.26}{25.25}\)

\(T=\frac{1.2.3...23.24}{2.3.4...24.25}.\frac{3.4.5...25.26}{2.3.4...24.25}\)

\(T=\frac{1}{25}.\frac{26}{2}\)

\(T=\frac{1}{25}.13\)

\(T=\frac{13}{25}\)

TK MK NHA

\(d=\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right).........\left(1+\frac{1}{99.101}\right)\)

    \(=\frac{4}{3}.\frac{9}{2.4}.............\frac{10000}{99.101}\)

    \(=\frac{2.2}{3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}............\frac{100.100}{99.101}\)

    \(=\frac{2.3.4..........100}{2.3.4............99}.\frac{2.3.4...........100}{3.4...........101}\)

     \(=100.\frac{2}{101}\)\(=\frac{200}{101}\)

\(C=\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times...\times\left(1-\frac{1}{1994}\right)\)

    \(=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times...\times\frac{1993}{1994}\)

    \(=\frac{1\times2\times3\times...\times1993}{2\times3\times4\times...\times1994}\)

    \(=\frac{1}{1994}\)                         (Giản ước còn lại như này)