\(=\dfrac{-56\left(12+18\right)}{56}=-30\)

\(1997-\left[10.\left(2^3-56\right):2^3+2^3\right].2005\)

\(=1997-\left[10.\left(8-56\right):8+8\right].2005\)

\(=1997-\left[10.\left(-48\right):8+8\right].2005\)

\(=1997-\left[\left(-60\right)+8\right].2005\)

\(=1997-\left(-52\right).2005\)

\(=1997-\left(-104260\right)=106257\)

1997-[10.(2³- 56): 2³+2³ ].2005

= 1997-[10.(8 - 56): 2³+2³ ].2005

= 1997-[10.(-48): 2³+2³ ].2005

= 1997-[10.(-48): 8 + 8 ].2005

= 1997-(-52).2005

= 106257

\(\left(x+34\right).2=56\)

          \(x+34=56\div2\)

          \(x+34=28\)

                      \(x=28-34\)

                      \(x=-6\)

(x+34) x 2=56

(x+34)=56:2

x+34=28

x=28-34

x=(-6)

\(2^x+3\cdot2^{x+1}=56\)

=>\(2^x+6\cdot2^x=56\)

=>\(7\cdot2^x=56\)

=>\(2^x=8\)

=>x=3

Ta có :

nx(n-1)=56

<=>nx(n-1)=8x7

<=>nx(n-1)=8x(8-1)

=> n=8

Ta có :

\(n.\left(n-1\right)=56\)

\(n.\left(n-1\right)=8.7\)

\(\Rightarrow n=8\)

\(\Leftrightarrow2\left(x+1\right)^3=56\Leftrightarrow\left(x+1\right)^3=28\Leftrightarrow\)

\(a,\Rightarrow x+2=-40\\ \Rightarrow x=-42\\ b,\Rightarrow6x-7-2x=5\\ \Rightarrow4x=12\Rightarrow x=3\\ c,\Rightarrow68-56-x=-2\\ \Rightarrow12-x=-2\\ \Rightarrow x=14\)

\(a,\left(x+3\right)\left(5-x\right)=0\\ \Rightarrow\left\{{}\begin{matrix}x+3=0\\5-x=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-3\\x=5\end{matrix}\right.\)

\(c,x+17⋮x+3\\ x+3+14⋮x+3\\ 14⋮x+3\\ x+3\inƯ\left(14\right)=\left\{\pm14;\pm7\pm2;\pm1\right\}\)

Từ đó bạn tìm những giá trị của x nha!

\(B=\left(4^5\cdot10\cdot5^6+25^5\cdot2^8\right):\left(2^8\cdot5^4+5^7\cdot2^5\right)\)

\(B=\dfrac{4^5\cdot10\cdot5^6+25^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)

\(B=\dfrac{\left(2^2\right)^5\cdot2\cdot5\cdot5^6+\left(5^2\right)^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)

\(B=\dfrac{2^{11}\cdot5^7+5^{10}\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)

\(B=\dfrac{2^8\cdot5^7\cdot\left(2^3\cdot1+5^3\cdot1\right)}{2^5\cdot5^4\cdot\left(2^3\cdot1+5^3\cdot1\right)}\)

\(B=\dfrac{2^8\cdot5^7}{2^5\cdot5^4}\)

\(B=\dfrac{2^3\cdot5^3}{1\cdot1}\)

\(B=\left(2\cdot5\right)^3\)

\(B=10^3\)

\(B=1000\)

bạn ơi ( 2² )⁵ là sao hả bạn