P=\(\frac{\left(2002+1\right)\times14+1988+2001\times2002}{2002\times\left(1+503+504\right)}\)

\(=\frac{2002\times14+2002+2001\times2002}{2002\times1008}\)

\(=\frac{2002\times\left(14+1+2001\right)}{2002\times1008}=\frac{2016}{1008}=2\)

1012 nhé bạn

diễn giải dùm mik đc k?

kết quả là bao nhiêu

bấm máy nha bạn

a)(44x52x60):(11x13x15)                                                                                                                                    =(44:11)x(52:13)x(60:15)=4x4x4      =64      

\(a.\)

\(\left(44.52.60\right):\left(11.13.15\right)=\frac{44.52.60}{11.13.15}\frac{4.4.4\left(11.13.15\right)}{\left(11.13.15\right)}=4^3=64\)

cho mình sửa một chút 1998->1988

\(\frac{2003\times14+1998+2001\times2002}{2002+2002\times503+504\times2002}=\frac{\left(2002+1\right)\times14+1998+2001\times2002}{2002\left(1+503+504\right)}=\frac{2002\times14+14+1998+2001\times2002}{2002\times1008}\)=\(\frac{2002\times14+2002\times2001+2002}{2002\times1008}=\frac{2002\left(14+2001+1\right)}{2002\times1008}=\frac{2002\times2016}{2002\times1008}\)=\(\frac{2016}{1008}=\frac{2}{1}=2\)

phân số thì không ra mà chỉ ra số thập phân thôi nha bạn

Kết Quả là: 2,000004955 nha. 

AAĂn loz

 2003 x 14 + 1988 + 2001 x 2002

=28042 + 1988 + 4006002

=4036032

 2002 + 2002 x 503 +504 x 2002

=2002 x 1 + 2002 x 503 + 504 x 2002

=2002 x (1 + 503 + 504)

=2002 x 908

=1817816

\(\frac{x+16}{2000}+1+\frac{x+15}{2001}+1=\frac{x+14}{2002}+1+\frac{x+13}{2003}+1\)

\(\frac{x+2016}{2000}+\frac{x+2016}{2001}=\frac{x+2016}{2002}+\frac{x+2016}{2003}\)

\(\frac{x+2016}{2000}+\frac{x+2016}{2001}-\frac{x+2016}{2002}-\frac{x+2016}{2003}=0\)

\(\left(x+2016\right)\left(\frac{1}{2000}+\frac{1}{2001}-\frac{1}{2002}-\frac{1}{2003}\right)=0\)

\(x-2016=0\)

\(x=2016\)