1/2;4/5;5/6;6/7;7/8;8/9 

1/2 ; 4/5 ; 5/6 ; 6/7 ; 7/8; 8/9

Có: \(\dfrac{1}{2}=0,5;\dfrac{5}{6}=0,8\left(3\right);\dfrac{4}{5}=0,8\)

\(\dfrac{7}{8}=0,875;\dfrac{6}{7}=0,\left(857142\right)\)

Vì 0,5 < 0,8 < 0,8(3) < 0,(857142) < 0,875

nên \(\dfrac{1}{2}< \dfrac{4}{5}< \dfrac{5}{6}< \dfrac{6}{7}< \dfrac{7}{8}\)

=> Các phân số đó khi viết theo thứ tự từ bé đến lớn là: \(\dfrac{1}{2};\dfrac{4}{5};\dfrac{5}{6};\dfrac{6}{7};\dfrac{7}{8}\)

1/2 < 4/5 < 5/6 < 6/7 < 7/8 < 8/9

1/2;4/5;5/6;6/7;7/8;8/9

1.1/2 ; 2/3 ; 3/4 ; 4/5 ; 5/6 .

2. 3/2 ; 13/12 ; 7/8 ; 15/22 .

3. 4/7

4. 5/4

Đáp án là 1/2,2/3,3/4,4/5,5/6,

\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)

\(1\frac{1}{2};1\frac{1}{3};1\frac{1}{4};1\frac{1}{5};1\frac{1}{6};1\frac{1}{7};1\frac{1}{8}\)\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)

Vì \(\frac{1}{2}>\frac{1}{3}>\frac{1}{4}>\frac{1}{5}>\frac{1}{6}>\frac{1}{7}>\frac{1}{8}\)

=> \(1\frac{1}{2}>1\frac{1}{3}>1\frac{1}{4}>1\frac{1}{5}>1\frac{1}{6}>1\frac{1}{7}>1\frac{1}{8}\)

Hay    \(\frac{3}{2}>\frac{4}{3}>\frac{5}{4}>\frac{6}{5}>\frac{7}{6}>\frac{8}{7}>\frac{9}{8}\)

\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)

\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)

9/8,8/7,7/6,6/5,5/4,4/2,3/2

bài 1:

các ps ....lớn đến bé là:

b1:8/10;14/20;27/40;5/8.

b2: (rút gọn)

5/8 ; 4/5 ; 7/10 ; 27/40.

mình nghĩ là : 1/2 < 2/3 < 3/4 < 4/5 < 5/6 < 6/7 < 7/8 < 8/9 < 9/10

Thankyou bạn

1/7;2/3;3/4;9/8;6/5

Ta có:
\(\dfrac{6}{5}=\dfrac{6\times168}{5\times168}=\dfrac{1008}{840}\)     ;    \(\dfrac{3}{4}=\dfrac{3\times210}{4\times210}=\dfrac{630}{840}\)     ;     \(\dfrac{9}{8}=\dfrac{9\times105}{8\times105}=\dfrac{945}{840}\) 

\(\dfrac{1}{7}=\dfrac{1\times120}{7\times120}=\dfrac{120}{840}\)     ;    \(\dfrac{2}{3}=\dfrac{2\times280}{3\times280}=\dfrac{560}{840}\)

⇒ \(\dfrac{120}{840}< \dfrac{560}{840}< \dfrac{630}{840}< \dfrac{945}{840}< \dfrac{1008}{840}\) ⇒ \(\dfrac{1}{7}< \dfrac{2}{3}< \)\(\dfrac{3}{4}< \dfrac{9}{8}< \dfrac{6}{5}\)