kết quả bằng 54 nha bạn  

                       nguyễn thị khánh ly

  (30 : 7,5 + 0,5 x 3 - 1,5) x (4,5 - 9 : 2)

= (30 : 7,5 + 0,5 x 3 - 1,5) x (4,5 - 4,5)

= (30 : 7,5 + 0,5 x 3 - 1,5) x 0

= 0

câu trên chuẩn

(4,5*16-1,7):4.5*15+2.8

=\(\frac{4,5\cdot16-1.7}{4,5\cdot15+2,8}\)                       

=\(\frac{4,5\cdot\left(15+1\right)-1.7}{4,5\cdot15+2,8}\) 

=\(\frac{4,5\cdot15+4,5-1,7}{4,5\cdot15+2.8}\) 

=\(\frac{4,5\cdot15+2,8}{4,5\cdot15+2,8}\) 

=1

2)a): 2,85 * 156,23 - 2,85 * 56,23 

=2,85 * ( 156,23 - 56,23 ) 

=2,85 * 100 

= 285

2)b): = 1,5+(1,8+4,2)+(2,1+3,9)+(2,4+3,6)+(2,7+3,3)+3

= 1,5+(6+6+6+6)+3

=1,5+24+3

=28,5

Bài 1: Tìm y biết (14,17 - y) * 2/9 = 1/3

Bài 2: Tính nhanh

2,85 * 156,23 - 2,85 * 56,23

___________________________

1,5 + 1,8 + 2,1 + 2,4 + 2,7 + 3 + 3,3 + 3,6 + 3,9 +4,2

Bài 3: Tìm x

13,44 * x - (16 + x) * 0,5 - 3,7 * (x - 0,9) = 13,618

a) 17,56 . 4,7 + 5,3 . 17,56 - 2,8

= 17,56 . ( 4,7 + 5,3 ) - 2,8

= 17,56 . 10 - 2,8

= 175,6 - 2,8

= 172,8

b) ( 2 . 4 . 8 . 0,5 . 0,25 . 1,25 ) : 0,1

= [ ( 2 . 0,5 ) . ( 4 . 0,25 ) . ( 8 . 1,25 ) ] : 0,1

= ( 1 . 1 . 10 ) : 0,1

= 10 : 0,1

= 100

3.a) Ta có: (x+1).(x-2) < 0

=> x+1 = 0  hoặc  x-2 = 0

=> x = 0-1 = -1  hoặc  x = 0+2 = 2

Vậy x = -1 hoặc x = 2

b) (x-2).(x+2/3) = ?

\(\Rightarrow\)x+1= 0   hoac x-2=0

\(\Rightarrow\)x+1=0                                          x-2=0

tu lam tiep

\(a,3-x=x+1,8\)

\(\Rightarrow-x-x=1,8-3\)

\(\Rightarrow-2x=-1,2\)

\(\Rightarrow x=0,6\)

\(b,2x-5=7x+35\)

\(\Rightarrow2x-7x=35+5\)

\(\Rightarrow-5x=40\)

\(\Rightarrow x=-8\)

\(c,2\left(x+10\right)=3\left(x-6\right)\)

\(\Rightarrow2x+20=3x-18\)

\(\Rightarrow2x-3x=-18-20\)

\(\Rightarrow-x=-38\)

\(\Rightarrow x=38\)

\(d,8\left(x-\dfrac{3}{8}\right)+1=6\left(\dfrac{1}{6}+x\right)+x\)

\(\Rightarrow8x-3+1=1+6x+x\)

\(\Rightarrow8x-3=7x\)

\(\Rightarrow8x-7x=3\)

\(\Rightarrow x=3\)

\(e,\dfrac{2}{9}-3x=\dfrac{4}{3}-x\)

\(\Rightarrow-3x+x=\dfrac{4}{3}-\dfrac{2}{9}\)

\(\Rightarrow-2x=\dfrac{10}{9}\)

\(\Rightarrow x=-\dfrac{5}{9}\)

\(g,\dfrac{1}{2}x+\dfrac{5}{6}=\dfrac{3}{4}x-\dfrac{1}{2}\)

\(\Rightarrow\dfrac{1}{2}x-\dfrac{3}{4}x=-\dfrac{1}{2}-\dfrac{5}{6}\)

\(\Rightarrow-\dfrac{1}{4}x=-\dfrac{4}{3}\)

\(\Rightarrow x=\dfrac{16}{3}\)

\(h,x-4=\dfrac{5}{6}\left(6-\dfrac{6}{5}x\right)\)

\(\Rightarrow x-4=5-x\)

\(\Rightarrow x+x=5+4\)

\(\Rightarrow2x=9\)

\(\Rightarrow x=\dfrac{9}{2}\)

\(k,7x^2-11=6x^2-2\)

\(\Rightarrow7x^2-6x^2=-2+11\)

\(\Rightarrow x^2=9\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)

\(m,5\left(x+3\cdot2^3\right)=10^2\)

\(\Rightarrow5\left(x+24\right)=100\)

\(\Rightarrow x+24=20\)

\(\Rightarrow x=-4\)

\(n,\dfrac{4}{9}-\left(\dfrac{1}{6^2}\right)=\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}\)

\(\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}=\dfrac{4}{9}-\dfrac{1}{36}\)

\(\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}=\dfrac{5}{12}\)

\(\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2=0\)

\(\Rightarrow x-\dfrac{2}{3}=0\Rightarrow x=\dfrac{2}{3}\)

#\(Urushi\text{☕}\)