\(\frac{2013\cdot2014-1902}{2013\cdot2013+111}=\frac{2013\cdot\left(2013+1\right)-1902}{2013\cdot2013+111}=\frac{2013\cdot2013+2013-1902}{2013\cdot2013+111}=\frac{2013\cdot2013+111}{2013\cdot2013+111}=1\)

=>đpcm

số số hạng dãy số là

(1902-1):1+1=1902(số)

tổng dãy số là

(1902+1)x1902:2=1809753

Số các số hạng là:

   (1902-1):1+1=1902(số hạng)

Tổng của dãy số là:;

   (1902+1)x1902:2=1809753

           Đs:1809753.

Tk mk nhé!Thank you nhiều!!!

1. It’s not easy for them to translate these poem into English.

They found it difficult to translate these poem into English

2. The man found a lot in gold in the island in 1902

It was the man who found a lot of gold in the island in 1902

The Wright brothersstarted flying in 1902.Their first flight was in a glider,which they designed to test the stability of its wings.Once they (1)....were.... satisfied that they could fly in the air steadily,without the fear (2)....of.... falling straight down,they began working on their design for the first aeroplane.(3)....It.... would be propelledby a motor.They wrote to several carmakers,asking (4)...if.... they could build a motor for them,but most either did not reply (5)....or.... said they were too busy.Finally,they decied to build the motor (6)...themselves.... The major problem they faced was how to make the motor powerful (7)...enough... to propel the aeroplane withoutbeing too heavy.They soon relised that they would need to make the aeroplane bigger,(8)...rather...than make the motor smaller.After months os planning,they were ready to build the first prototype.It was a looking machine (9)....with.... four wings and no seat for the pilot.The two brothers were very (10)....proud... of their invention but could not decide (11)...who... would be the one to fly it.They tossed a coin and Wilbur won.The world's first ever aeroplane (12)...took.... off and flew into the air,making history.

Lời giải:

Gọi $R(x)$ là đa thức dư khi chia $P(x)$ cho $(x-1)(x-2)(x-3)(x-4)$. Bậc của $R(x)$ phải nhỏ hơn bậc đa thức chia. Do đó đặt:

\(R(x)=ax^3+bx^2+cx+d\)

\(P(x)=Q(x)(x-1)(x-2)(x-3)(x-4)+ax^3+bx^2+cx+d\)

Trong đó $Q(x)$ là đa thức thương.

Theo định lý Bê-du về phép chia đa thức:

\(\left\{\begin{matrix} P(1)=a+b+c+d=-2019\\ P(2)=8a+4b+2c+d=-2036\\ P(3)=27a+9b+3c+d=-2013\\ P(4)=64a+16b+4c+d=-1902\end{matrix}\right.\)

\(\Rightarrow \left\{\begin{matrix} a=8\\ b=-28\\ c=11\\ d=-2010\end{matrix}\right.\)

Vậy \(R(x)=8x^3-28x^2+11x-2010\)

b)

Từ phần a suy ra:

\(\left\{\begin{matrix} R(1)=P(1)=-2019\\ R(2)=P(2)=-2036\\ R(3)=P(3)=-2013\\ R(4)=P(4)=-1902\\ R(5)=8.5^3-28.5^2+11.5-2010=-1655\end{matrix}\right.\)

a)9<58<743<68 247<1 258 647

b)34 108<58 610<60 000<78 645<84 364

c)1290<1902<2019<2910<9021<9201

d)111<211<212<221<222<1112

a,9;58;743;68247;1258647

b,34108;58610;60000;78645;84364

c,1290;1902;2019;2910;9021;9201

d,111;211;212;221;222;1112

Mk nghĩ cái này nó ko khó, bn có thể tự làm đc mà!!! Câu nào khó ms hỏi nhé!!!

Sắp xếp theo thứ tự tăng dần :

a) \(9;58;743;68247;1258647.\)

b) \(34108;58610;60000;78645;84364.\)

c) \(1290;1902;2019;2910;9021;9201.\)

d) \(111;211;212;221;222;1112.\)

bang 0

1902 x 1209 x 3890 x 111 : 0=0 <vì tất cả các số chia cho 0 đều = 0>

Học tốt

&YOUTUBER&