\(\frac{2^{15}.9^4}{6^3.8^3}\)=\(\frac{2^{15}.\left(3^2\right)^3}{\left(2.3\right)^3.\left(2^3\right)^3}\)=\(\frac{2^{15}.3^6}{2^3.3^3.2^9}\)=\(\frac{2^{15}.3^6}{2^{12}.3^3}\)=\(2^3.3^3\)=8.27=216

3¹⁷.81¹¹/27¹⁰.9¹⁵

=3¹⁷.(3⁴)¹¹/(3³)¹⁰.(3²)¹⁵

=3¹⁷.3⁴⁴/3³⁰.3³⁰

=3⁶¹/3⁶⁰

=3

\(\frac{3^{17}.81^{11}}{27^{10}.9^{15}}=\frac{3^{17}.\left(3^4\right)^{11}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\frac{3^{17}.3^{41}}{3^{30}.3^{30}}=\frac{3^{17+41}}{3^{30+30}}=\frac{3^{58}}{3^{60}}=\frac{1}{3^2}=\frac{1}{9}\)

nho k day

a/ \(\left(-0,125\right)^3:80^4=-\frac{1}{512}.80^4=-80000\)

b/ \(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=3\)

a, ( - 0, 125)^3 . 80^ 4 

   \(\left(-\frac{1}{8}\right)^3.80^4=\frac{-1^3}{8^3}\cdot8^4\cdot10^4\)  = \(-8\cdot10^4=-8.1000=-8000\)

b,\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{3^{4.11}.3^{17}}{3^{3.10}.3^{2.15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{44+17}}{3^{30+30}}=\frac{3^{61}}{3^{60}}=3\)

kệ cha nhà bây

a)   378

b)   3

c)    2

d)    2

e)    \(\frac{8748}{1715}\)

Mình thấy bài e) bạn có ghi thiếu ko vậy.81^2 x;: hay là cộng trừ vậy?

\(3^{17}.81^{11}:27^{10}.9^{15}\)

=\(3^{17}.\left(3^4\right)^{11}:\left(3^3\right)^{10}.\left(3^2\right)^{15}\)

=\(3^{17}.3^{44}:3^{30}.3^{30}\)

=\(3^{17+44-30+30}\)

=\(3^{61}\)

hehe ko có ji