18/49

20/7

14/11

3/35

1. \(-\dfrac{1}{5}-\left(-\dfrac{2}{3}\right)=\dfrac{-1}{5}+\dfrac{2}{3}=\dfrac{7}{15}.\)

2. \(-\dfrac{2}{5}-\dfrac{1}{7}=\dfrac{-14-5}{35}=\dfrac{-19}{35}.\)

3. \(\dfrac{3}{5}-\dfrac{5}{7}=\dfrac{21-25}{35}=\dfrac{-4}{35}.\)

4. \(\dfrac{4}{7}+\dfrac{-5}{8}-\dfrac{3}{28}=\dfrac{32-35-6}{56}=\dfrac{-9}{56}.\)

1: \(=\dfrac{-1}{5}+\dfrac{2}{3}=\dfrac{-3+10}{15}=\dfrac{7}{15}\)

2: \(=\dfrac{-14}{35}-\dfrac{5}{35}=-\dfrac{19}{35}\)

3: \(=\dfrac{21}{35}-\dfrac{25}{35}=-\dfrac{4}{35}\)

4: \(=\dfrac{32}{56}-\dfrac{35}{56}-\dfrac{6}{56}=\dfrac{-9}{56}\)

a >

b <

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d <

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đề thiếu bạn ơi

hoặc đề sai

..............

bn viết thiếu đề nhé

A= 71 + 72 + 73 + 74 = (71+74)+(72+73) = 145 + 145 = 290 chia hết cho 5

=> A=........ chia hết cho 5

B=  10⁶-5⁷ = 2⁶. 5⁶ - 5⁷ = 5⁶ ( 2⁶ - 5) =(5⁶ . 59) chia hết cho 59 => B chia hết cho 59

1: \(=-\dfrac{3}{4}+3-\dfrac{1}{4}-\dfrac{5}{4}+\dfrac{9}{2}=-\dfrac{9}{4}+3+\dfrac{9}{2}=\dfrac{-9+12+18}{4}=\dfrac{21}{4}\)

2: \(=\dfrac{-5}{7}\left(\dfrac{13}{19}+\dfrac{6}{19}\right)+\dfrac{5}{7}=\dfrac{-5}{7}+\dfrac{5}{7}=0\)

3: \(=\dfrac{2}{5}\left(1-\dfrac{8}{3}-\dfrac{5}{8}\right)=\dfrac{2}{5}\cdot\dfrac{-55}{24}=\dfrac{-11}{12}\)

câu này để mình bày cho

ơ...... mình không biết

Giải hộ mik vs mik cần gấp

F = 7 + 72 + 73 + 74 + ..... + 7100 

F= 7+(1+7)+73+(1+7)+...+799+(1+7)

F = 7x8+73x8+...+799x8

F= 8x(7+73+...+799)

mà 8 chia hết 8 => 8(7+73+...+799) chia hết 8

Vậy F chia hết cho 8

2)

\(F=7+7^2+7^3+7^4+...+7^{100}\\ F=7\cdot\left(1+7\right)+7^3\cdot\left(1+7\right)+.....+7^{99}\cdot\left(1+7\right)\\F=7\cdot8+7^3\cdot8+.....+7^{99}\cdot8\\ F=8\cdot\left(7+7^3+....+7^{99}\right)\\ =>F⋮8\) 

1: Ta có: 7x+6(3-x)=27-20+73

\(\Leftrightarrow7x+18-6x=80\)

\(\Leftrightarrow x=80-18=62\)

Vậy: x=62

2: Ta có: \(6x-5\left(x-7\right)=\left(27-514\right)-486-73\)

\(\Leftrightarrow6x-5x+35=27-514-486-73\)

\(\Leftrightarrow x+35=-1046\)

\(\Leftrightarrow x=-1081\)

Vậy: x=-1081

thanks you