a) 135 + x -135 = 0 => (135 - 135) + x = 0 => x = 0.

b) -562 - x + 562 = 0 => (-562 + 562) - x = 0 => - x = 0 => x = 0.

c) 61 + x - 23 = 91=> (61 - 23) + x = 91=>38 + x = 91=> x = 53.

d) 11 + 53 - x = 97 => 64 - x = 97 => x = 64 - 97 => x = - 33

a) \(\frac{304}{60}=\frac{9}{135}-x\)

\(\Rightarrow x=\frac{9}{135}-\frac{304}{60}\)

\(\Rightarrow x=-5\).

Vậy \(x=-5.\)

b) \(\frac{-1}{2}+\frac{16}{124}+x-\frac{5}{31}=\frac{2}{62}\)

\(\Rightarrow\frac{-1}{2}+\frac{4}{31}+x-\frac{5}{31}=\frac{1}{31}\)

\(\Rightarrow\frac{-1}{2}+x=\frac{1}{31}-\frac{4}{31}+\frac{5}{31}\)

\(\Rightarrow\frac{-1}{2}+x=\frac{2}{31}\)

\(\Rightarrow x=\frac{2}{31}-\frac{-1}{2}\)

\(\Rightarrow x=\frac{35}{62}\)

Vậy \(x=\frac{35}{62}\)

c) \(\frac{2}{17}+\frac{15}{24}-\frac{15}{27}-x-\frac{8}{23}=0\)

\(\Rightarrow\left(\frac{2}{17}+\frac{5}{8}-\frac{5}{9}\right)-x=\frac{8}{23}\)

\(\Rightarrow\frac{229}{1224}-x=\frac{8}{23}\)

\(\Rightarrow x=\frac{229}{1224}-\frac{8}{23}\)

\(\Rightarrow x=\frac{-4525}{28152}\)

Vậy \(x=\frac{-4525}{28152}\)

\(\Rightarrow x=\frac{385}{186}\).

Bài 2: 

a: =>x-45=-20

hay x=25

b: =>35+30-5x=-12+112

=>65-5x=100

=>5x=-35

hay x=-7

c: =>x-124=1000

hay x=1124

d: \(\Leftrightarrow46-\left(3x-2\right)^3=-18\)

\(\Leftrightarrow\left(3x-2\right)^3=64\)

=>3x-2=4

hay x=2

Bài 2: 

a: =>x-45=-20

hay x=25

b: =>35+30-5x=-12+112=100

=>65-5x=100

=>5x=-35

hay x=-7

c: =>x-124=1000

hay x=1124

d: \(\Leftrightarrow46-\left(3x-2\right)^3=-18\)

\(\Leftrightarrow\left(3x-2\right)^3=64\)

=>3x-2=4

hay x=2

sao bạn ko làm bài 1 cho mình zậy

Đáp án: 135 x 80 + 20 x 135    =   135 x ( 80 + 20 )

=135(37+64-1)=135*100=13500

135 x 37 + 135 +  62 x 135

= 135 x 37 + 135 x 1 +  62 x 135

= 135 x ( 37 + 1 + 62)

 = 135 x 100

= 13500