chung minh B/A là một ô nguyên biêt rang :
A=1/2+1/3+1/4+...+1/2013
B=2012/1+2011/2+2010/3+...+1/2012
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chung minh B/A là một ô nguyên biêt rang :
A=1/2+1/3+1/4+...+1/2013
B=2012/1+2011/2+2010/3+...+1/2012
\(\frac{B}{A}=\frac{\frac{2012}{1}+\frac{2011}{2}+\frac{2010}{3}+...+\frac{1}{2012}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2013}}\)
\(=\frac{\left(\frac{2011}{2}+1\right)+\left(\frac{2010}{3}+1\right)+...+\left(\frac{1}{2012}+1\right)+1}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2013}}\)
\(=\frac{\frac{2013}{2}+\frac{2013}{3}+\frac{2013}{4}+....+\frac{2013}{2012}+\frac{2013}{2013}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2013}}\)
\(=\frac{2013\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2013}\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2013}}=2013\)
\(B=\frac{2012}{1}+\frac{2011}{2}+\frac{2010}{3}+....+\frac{1}{2012}\)
\(=1+\left(\frac{2011}{2}+1\right)+\left(\frac{2010}{3}+1\right)+....+\left(\frac{1}{2012}+1\right)\)
\(=\frac{2013}{2}+\frac{2013}{3}+.....+\frac{2013}{2012}+\frac{2013}{2013}\)
\(=2013\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2013}\right)\)
\(\Rightarrow\frac{B}{A}=\frac{2013\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2013}\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2013}}=2013\)