a, x - 426 = 2478

x = 2478 + 426

x = 2904

b, 1452: x = 4

x = 1452 : 4

x = 363

a) x = 2094          b) x = 383

x- 32:16=48

=>x-2=48

=>x=48+2

=>x=50

(x-32):16=48

=>x-32= 48x 16

=>x-32= 768

=>x=768+32

=>x=800

1.x=50

2.x=bấm máy tính nhá mik hơi bí chút

k ủng hộ nhá

ta có (x+16)/(x+1) = (x+15+1)/(x+1) = (x+1)/((x+1)+ 15/(x+1)=1+15/(x+1) 
để (x+16) chia hết cho (x+1) thì x+1 phải là ước của 15 tức là 
(x+1) thuộc { 1,3,5,15} 
* x+1=1 => x=0 
* x+1 = 3 => x=2 
* x+1 = 5 => x =4 
* x+1 = 15 => x=14

x+16 chia hết cho x+1

=> x+16=(x+1)+15

=>15 chia hết cho x+1

=>x+1\(\in\){1;3;5;15}

=>x\(\in\){0;2;4;14}

\(\Leftrightarrow164-4\left(x-5\right)=80\\ \Leftrightarrow4\left(x-5\right)=84\\ \Leftrightarrow x-5=21\Leftrightarrow x=26\)

a.

\(A=B\)

\(\Leftrightarrow\dfrac{x+2}{x-2}-\dfrac{x-2}{x+2}=\dfrac{-16}{x^2-4}\);ĐK:\(x\ne\pm2\)

\(\Leftrightarrow\dfrac{\left(x+2\right)^2-\left(x-2\right)^2}{\left(x-2\right)\left(x+2\right)}=\dfrac{-16}{\left(x-2\right)\left(x+2\right)}\)

\(\Leftrightarrow\left(x+2\right)^2-\left(x-2\right)^2=-16\)

\(\Leftrightarrow x^2+4x+4-x^2+4x-4+16=0\)

\(\Leftrightarrow8x+16=0\)

\(\Leftrightarrow8\left(x+2\right)=0\)

\(\Leftrightarrow x=-2\left(ktm\right)\)

Vậy không có giá trị x thỏa mãn A=B

b.

\(A:B=\dfrac{\left(x+2\right)^2-\left(x-2\right)^2}{\left(x-2\right)\left(x+2\right)}:\dfrac{-16}{\left(x-2\right)\left(x+2\right)}< 0\)

\(\Leftrightarrow\dfrac{x^2+4x+4-x^2+4x-4}{-16}< 0\)

\(\Leftrightarrow\dfrac{8x}{-16}< 0\)

\(\Leftrightarrow\dfrac{8x}{16}>0\)

\(\Leftrightarrow\dfrac{x}{2}>0\)

\(\Leftrightarrow x>0\)

\(x+\dfrac{1}{2}+\dfrac{3}{8}=\dfrac{17}{16}\\ x+\dfrac{7}{8}=\dfrac{17}{16}\\ x=\dfrac{17}{16}-\dfrac{7}{8}\\ x=\dfrac{3}{16}\)

 18 . ( x-16 ) = 18 

x-16 = 18 : 18 

x- 16 = 1

x= 16+1

x= 17 

18 (x - 16) = 18

18 (x - 16) = 18 . 1

Vì 18 = 18 

=> x - 16 = 1

=> x = 17

Vậy x = 17.