a ) 62 - 4 x 6 + 48                       b ) 96 - 32 : 4  - 49

= 62 - 24 + 48                               = 96 - 8 - 49

= 38 + 48                                     = 86 - 49     

= 86                                            = 37

ai thấy đúng thì tk mk nha

ai tk mk mk tk lại

a ) 86

b ) 39

Câu 4:

\(4^{n+2}-4^{n-1}=252\\ \Leftrightarrow4^{n-1}.\left(4^3-1\right)=252\\ \Leftrightarrow4^{n-1}.63=252\\ \Leftrightarrow4^{n-1}=\dfrac{252}{63}=4=4^1\\ \Rightarrow n-1=1\\ \Rightarrow n=2\)

helpppp 

https://hoc24.vn/cau-hoi/.8233894147886

\(\sqrt{15-6\sqrt{6}}+\sqrt{35-12\sqrt{6}}=\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(3\sqrt{3}-2\sqrt{2}\right)^2}\)

\(=3-\sqrt{6}+3\sqrt{3}-2\sqrt{2}\)

\(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}=\sqrt{\left(3-2\sqrt{2}\right)^2}+\sqrt{\left(3+2\sqrt{2}\right)^2}\)

\(=3-2\sqrt{2}+3+2\sqrt{2}=6\)

\(\sqrt{49-5\sqrt{96}}+\sqrt{49+5\sqrt{96}}=\sqrt{\left(5-2\sqrt{6}\right)^2}+\sqrt{\left(5+2\sqrt{6}\right)^2}\)

\(=5-2\sqrt{6}+5+2\sqrt{6}=10\)

\(\sqrt{13-\sqrt{160}}+\sqrt{53+4\sqrt{90}}=\sqrt{\left(2\sqrt{2}-\sqrt{5}\right)^2}+\sqrt{\left(3\sqrt{5}+2\sqrt{2}\right)^2}\)

\(=2\sqrt{2}-\sqrt{5}+3\sqrt{5}+2\sqrt{2}=2\sqrt{5}+4\sqrt{2}\)

a: \(\sqrt{15-6\sqrt{6}}+\sqrt{35-12\sqrt{6}}\)

\(=3-\sqrt{6}+3\sqrt{3}-2\sqrt{2}\)

b: \(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}\)

\(=3-2\sqrt{2}+3+2\sqrt{2}\)

=6

c: Ta có: \(\sqrt{49-5\sqrt{96}}+\sqrt{49+5\sqrt{96}}\)

\(=5-2\sqrt{6}+5+2\sqrt{6}\)

=10

d: Ta có: \(\sqrt{13-\sqrt{160}}+\sqrt{53+4\sqrt{90}}\)

\(=\sqrt{13-4\sqrt{10}}+\sqrt{53+4\sqrt{90}}\)

\(=2\sqrt{2}-\sqrt{5}+3\sqrt{5}+2\sqrt{2}\)

\(=2\sqrt{5}+4\sqrt{2}\)

a) x - 452 = 77 + 48

x - 452 = 125

x= 125 + 452 

x= 577

b) x + 58 = 64 + 58

x + 58 = 122

x= 122 - 58

x= 64

c) x - 1 - 2 - 3 - 4 = 0

x= 0 + 4 + 3 + 2 +1

x= 10

a)x-452=77+48

x-452=125

x=125+452

x=577

b)x+58=64+58

x+58=122

x=122-58

x=64

c)x-1-2-3-4=0

x=0+4+3+2+1

x=10

Nhớ tick cho mk nha^^

a) \(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-3}{97}+\frac{x-4}{96}=4\)

\(\Rightarrow\frac{x-1}{99}-1+\frac{x-2}{98}-1+\frac{x-3}{97}-1+\frac{x-3}{96}-1=4-4\)

\(\Rightarrow\frac{x-100}{99}+\frac{x-100}{98}+\frac{x-100}{97}+\frac{x-100}{96}=0\)

\(\Rightarrow\left(x-100\right)\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)

\(\Rightarrow x-1=0\) ( vì \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\ne0\) )

Vậy x = 1

b) \(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}=3\)

\(\Rightarrow\frac{x+1}{99}+1+\frac{x+2}{98}+1+\frac{x+3}{97}+1=3-3\)

\(\Rightarrow\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}=0\)

\(\Rightarrow\left(x+100\right).\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}\right)=0\)

Vì \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}\ne0\)

=> x + 100 = 0

=> x           = -100

c) \(\frac{x-1}{99}+\frac{x-2}{49}+\frac{x-4}{32}=6\)

\(\Rightarrow\frac{x-1}{99}-1+\frac{x-2}{49}-2+\frac{x-4}{32}-3=6-6\)

\(\Rightarrow\frac{x-100}{99}+\frac{x-100}{49}+\frac{x-100}{32}=0\)

\(\Rightarrow\left(x-100\right)\left(\frac{1}{99}+\frac{1}{49}+\frac{1}{32}\right)=0\)

Vì \(\frac{1}{99}+\frac{1}{49}+\frac{1}{32}\ne0\)

=> x - 100 = 0

=> x           = 100

Chúc bạn học tốt

có người khác trả lời trước rồi nên chị ko trả lời đâu nhé em trai

Tính hợp lí

a,15.(27+ 18 +6 ) + 15.( 23 +12)

  = 15(27+18+6+23+12)

  = 15.86

  = 1290

b,24.(15 + 49 ) + 12. ( 50 + 42 )

=12.2(15+49)+12.(50+42)

= 12(30+98)+12(50+42)

=12(30+98+50+42)

=12.220

= 2640

c,53.(51+4)+53.(49+96) +53

=53(51+4)+53(49+96)+53.1

=53(51+4+49+96+1)

=53.201

=10653

d,42.( 15 +96) +6.(25 +4).7  

=42(15+96)+42(25+4)

=42(15+96+25+4)

=42.140

=5880

tick đúng cho mk nha pikachu

20-2.(x+14)=16

a)\(A=\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{96}+\frac{2}{192}\)

\(\frac{1}{2}xA=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}\)

\(\frac{1}{4}xA=\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}+\frac{1}{384}\)

\(\frac{1}{4}xA-\frac{1}{2}xA=\frac{1}{3}-\frac{1}{384}\)

\(\frac{1}{4}xA=\frac{127}{384}\)

\(A=\frac{127}{384}:\frac{1}{4}\)

\(A=\frac{127}{96}\)

\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)

\(=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+...+1-\frac{1}{90}\)

\(=9-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)

\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)

\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{9}-\frac{1}{10}\right)\)

\(=9-\left(1-\frac{1}{10}\right)\)

\(=9-\frac{9}{10}=\frac{81}{10}\)

a)16.4^x=4⁸

^{\(4^2.4^x=4^{8^{ }}\)}

^{\(4^x=4^{8^{ }}:4^2\)}

\(4^x=4^{6^{ }}\)

\(x=6\)
b)(X-2)(X-5)=0

\(\Rightarrow x-2=0\rightarrow x=2\)

\(x-5=0\rightarrow x=5\)

Vậy x∈ {2;5}
c)2^x+2^x+1=96

\(2^x.1+2^{x^{ }}.2\)

\(2^x.\left(1+2\right)=96\)

\(2^x.3=96\)

\(2^x=96:3\)

\(2^x=32\)

\(2^x=2^5\)

\(x=5\)

\(Zzz\) 😪

chị giúp em đc mấy bài trong trang của em mới đăng đc ko ạ?

a) Số các số hạng là:

( 99-49):2+1​\(=\)​26 ( số )

Tổng của dãy số trên là:

 ( 99 + 49 ) x 26 : 2 \(=\)1924

Đáp số: 1924

b) \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}+\frac{1}{32}-\frac{1}{64}+\frac{1}{64}-\frac{1}{128}\)

\(=\frac{1}{1}-\frac{1}{128}\)

\(=\frac{127}{128}\)

a) Số các số hạng là (99 - 49) : 2 + 1 = 26 số

Tổng của dãy trên là:

(99 + 49) x 26 : 2 = 1924

Đáp số : 1924

b) 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128

= 1/1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + 1/8 - 1/16 + 1/16 - 1/32 + 1/32 - 1/64 + 1/64 - 1/128

= 1/1 - 1/128

= 127/128