Ta có: \(71+\left(65\times4\right)=\frac{y+140}{y+260}\)

\(\Leftrightarrow331=\frac{y+140}{y+260}\)

\(\Leftrightarrow331\left(y+260\right)=y+140\)

\(\Leftrightarrow331y+86060=y+140\)

\(\Leftrightarrow331y-y=140-86060\)

\(\Leftrightarrow330y=-85920\)

\(\Leftrightarrow y=\frac{-85920}{330}=\frac{-2864}{11}\)

\(a,\)\(71+65\times4=\frac{x+140}{x}+260\)

\(\Rightarrow71+260=\frac{x-140}{x}+260\)

\(\Rightarrow71=\frac{x-140}{x}\)

\(\Rightarrow71x=x-140\)

\(\Rightarrow71x-x=-140\)

\(\Rightarrow70x=-140\)

\(\Rightarrow x=-2\)

\(b,\)\(y\times\frac{15}{2}-\frac{1}{3}\times\left(\frac{1}{4}+y\right)=90\frac{2}{3}\)

\(\Rightarrow\frac{15y}{2}-\frac{1}{12}-\frac{y}{3}=\frac{272}{3}\)

\(\Rightarrow\frac{90y}{12}-\frac{1}{12}-\frac{4y}{12}=\frac{1088}{12}\)

\(\Rightarrow90y-1-4y=1088\)

\(\Rightarrow86y=1089\)

\(\Rightarrow y=\frac{1089}{86}\)

a.1 là phân số nhé. Các bạn giúp mình với mình đang cần gấp

a) Ta có:

\(\begin{array}{l}\frac{x}{3} = \frac{y}{4} \Rightarrow \frac{x}{3}.\frac{1}{5} = \frac{y}{4}.\frac{1}{5} \Rightarrow \frac{x}{{15}} = \frac{y}{{20}};\\\frac{y}{5} = \frac{z}{6} \Rightarrow \frac{y}{5}.\frac{1}{4} = \frac{z}{6}.\frac{1}{4} \Rightarrow \frac{y}{{20}} = \frac{z}{{24}}\end{array}\)

Vậy  \(\frac{x}{{15}} = \frac{y}{{20}} = \frac{z}{{24}}\) (đpcm)

b) Áp dụng tính chất của dãy tỉ số bằng nhau, ta có:

\(\frac{x}{{15}} = \frac{y}{{20}} = \frac{z}{{24}} = \frac{{x - y + z}}{{15 - 20 + 24}} = \frac{{ - 76}}{{19}} =  - 4\)

Vậy x = 15 . (-4) = -60; y = 20. (-4) = -80; z = 24 . (-4) = -96

\(\frac{180\times123+9\times4567\times2+5310\times6}{\left(2+4+6+...+20+22\right)+48}\)

\(=\frac{18\times123+18\times4567+5310\times6}{132}\)

\(=\frac{116280}{132}=\frac{9690}{11}\)

mình bí rồi 

a) \(24\times y+76\times y=100\)
\(\Rightarrow\left(24+76\right)\times y=100\)
\(\Rightarrow100\times y=100\)
\(\Rightarrow y=100:100\)
\(\Rightarrow y=1\)
b) \(125\times y-100\times y=1000\)
\(\Rightarrow\left(125-100\right)\times y=1000\)
\(\Rightarrow25\times y=1000\)
\(\Rightarrow y=1000:25\)
\(\Rightarrow y=40\)

a)\(=>y=1000:\left(24+76\right)=1000:100=10\)

b(\(=>y=1000:\left(125-100\right)=1000:25=40\)