\(\frac{2929-101}{2.1919+404}\)

\(=\frac{101.\left(29-1\right)}{101\left(2.19+4\right)}\)

\(=\frac{28}{38+4}\)

\(=\frac{28}{42}\)

\(=\frac{2}{3}\)

Ta có : 

\(\frac{2929-101}{2.1919+404}\)

\(=\frac{29.101-101}{2.19.101+4.101}=\frac{101\left(29-1\right)}{101\left(2.19+4\right)}=\frac{28}{38+4}=\frac{28}{42}=\frac{2}{3}\)

Ủng hộ mk nha !!! ^_^

Bài giải

a) Ta có : \(\frac{4545+101}{6969-303}=\frac{45.101+101}{69.101-101.3}=\frac{101.\left(45+1\right)}{101.\left(69-3\right)}=\frac{101.46}{101.66}=\frac{23}{33}\)

b) Ta có : \(\frac{2929-101}{2.1919+404}=\frac{29.101-101}{2.19.101+4.101}=\frac{101.\left(29-1\right)}{101.\left(19.2+4\right)}=\frac{28}{42}=\frac{2}{3}\)

a)\(\frac{4545+101}{6969-303}\)= \(\frac{\left(4545:45\right)+101}{\left(6969:69\right)-303}\)= \(\frac{101+101}{101-303}\)=\(\frac{202}{-202}\)=-1 

b)\(\frac{2929-101}{2.1919+404}\)= \(\frac{2929-101}{3838+404}\)=\(\frac{\left(2929:29\right)-101}{\left(3838:38\right)+404}\)=\(\frac{101-101}{101+404}\)=\(\frac{0}{505}\)=0

học tốt 

2929-101

___________

2.1919+404

   2929-101*1

=_____________

   2.1919+101*4

  2929-1*1

=____________ 

   2.1919+1*4

  2929-1

=__________

  2.1919+4

  2928

=_____

  6.1919

\(\frac{101.29-101.1}{2.101.19+101.4}\)

\(=\frac{101.\left(29-1\right)}{101.\left(2.19+4\right)}\)

\(=\frac{28}{38+4}\)

\(=\frac{28}{42}=\frac{2}{3}\)

\(\frac{2929-101}{2.1919+404}=\frac{29.101-101}{2.19.101+101.4}=\frac{101.\left(29-1\right)}{101.\left(2.19+4\right)}=\frac{28}{42}=\frac{2}{3}\)

\(\frac{2}{3}\)

\(\frac{2929-101}{2.1919+404}=\frac{29.101-101}{2.19.101+4.101}=\frac{28.101}{42.101}=\frac{2}{3}\)

đáp án = 2/3 đấy bn !!!

\(\frac{13.\left(2929-101\right)}{2.1919+404}=\frac{13\left(101.29-101\right)}{2.101.19+101.4}=\frac{13.101\left(29-1\right)}{2.101\left(19+2\right)}=\frac{13.28}{2.21}=\frac{13.2}{3}=\frac{26}{3}\)

\(\frac{26}{3}\)