Câu hỏi đâu e?

a: Đối tượng là diện tích lúa và ngô

Tiêu chí là số lượng diện tích lúa và ngô

b: Tổng diện tích lúa trong 4 năm từ 2017->2020 là:

7705,2+7570,9+7469,9+7278,9=30024,9(nghìn ha)

Tổng diện tích ngô trong 4 năm từ 2017->2020 là:

1099,5+1032,9+986,7+942,5=4061,6(nghìn ha)

=>Nhiều hơn 25963,3(nghìn ha)

c: Tỉ số phần trăm là:

7278,9/30024,9=24,24%

2(x+3)=4x-(2+x)

<=>2x+6=4x-2-x

<=>2x+6-3x+2=0

<=> 8-x=0

<=> x=8

mệt

refer

https://www.google.com/search?q=2(x%2B3)%3D4x-(2%2Bx)&sourceid=chrome&ie=UTF-8

2(x+3)=4x-(2+x) 
2x+6=4x-2-x=3x-2
3x-2x=6+2
x=8

a: =-4*7*125*3=-500*21=-10500

b: =-24(21*2-142)

=-24*(-100)=2400

c: \(=-65\cdot87+65\cdot17-87\cdot17+87\cdot65=17\cdot\left(-22\right)=-374\)

d: \(=11\left(-31-43-26\right)=-11\cdot100=-1100\)

e: \(=\left(-168\right)\left(1+72+27\right)=-16800\)

j: \(=53\left(25-89-36\right)=53\cdot\left(-100\right)=-5300\)

Câu f đâu ạ

a: \(-6\cdot\left(-\dfrac{2}{3}\right)\cdot0.25=6\cdot\dfrac{2}{3}\cdot\dfrac{1}{4}=4\cdot\dfrac{1}{4}=1\)

b: \(\dfrac{-15}{4}\cdot\dfrac{-7}{15}\cdot\left(-2\dfrac{2}{5}\right)\)

\(=\dfrac{7}{4}\cdot\dfrac{12}{5}\)

\(=\dfrac{84}{20}=\dfrac{21}{5}\)

c: \(\left(-2\dfrac{1}{5}\right)\cdot\left(-\dfrac{9}{11}\right)\cdot\left(-\dfrac{1}{14}\right)\cdot\dfrac{2}{5}\)

\(=-\dfrac{11}{5}\cdot\dfrac{2}{5}\cdot\dfrac{9}{11}\cdot\dfrac{1}{14}\)

\(=-\dfrac{11}{11}\cdot\dfrac{2}{14}\cdot\dfrac{9}{25}\)

\(=-\dfrac{9}{175}\)

\(a,=4\cdot0,25=1\\ b,=\dfrac{7}{4}\cdot\left(-\dfrac{12}{5}\right)=-\dfrac{21}{5}\\ c,=\left(-\dfrac{11}{5}\right)\left(-\dfrac{9}{11}\right)\left(-\dfrac{15}{14}\right)\cdot\dfrac{2}{5}\\ =\dfrac{9}{5}\cdot\left(-\dfrac{15}{14}\right)\cdot\dfrac{2}{5}=-\dfrac{27}{14}\cdot\dfrac{2}{5}=-\dfrac{27}{35}\\ d,=\left(-\dfrac{11}{2}\right)\left(-\dfrac{1}{2}\right)+\dfrac{4}{9}=\dfrac{11}{4}+\dfrac{4}{9}=\dfrac{115}{36}\\ e,=\dfrac{5}{4}\cdot\left(-\dfrac{8}{15}\right)-\dfrac{3}{5}-\dfrac{3}{10}=-\dfrac{2}{3}-\dfrac{3}{5}-\dfrac{3}{10}=-\dfrac{47}{30}\)

\(f,B=\dfrac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\dfrac{2^{12}\cdot3^{10}\left(1+5\right)}{2^{11}\cdot3^{11}\left(6-1\right)}=\dfrac{2\cdot6}{5\cdot3}=\dfrac{4}{5}\\ g,=\dfrac{5}{8}+\dfrac{9}{4}\cdot\dfrac{5}{3}-\dfrac{5}{24}=\dfrac{5}{8}+\dfrac{15}{4}-\dfrac{5}{24}=\dfrac{25}{6}\\ h,=\dfrac{49}{38}\cdot\left(\dfrac{152}{11}-\dfrac{57}{11}\right):\dfrac{245}{418}=\dfrac{49}{38}\cdot\dfrac{418}{245}\cdot\dfrac{95}{11}=\dfrac{95\cdot11}{5\cdot11}=19\\ k,=\dfrac{11}{30}+\dfrac{18}{35}\cdot\dfrac{35}{54}-\dfrac{18}{35}\cdot\dfrac{49}{18}-\dfrac{18}{35}\cdot\dfrac{28}{48}\\ =\dfrac{11}{30}+\dfrac{1}{3}-\dfrac{7}{5}-\dfrac{3}{10}=-1\)

https://hoc24.vn/cau-hoi/giai-het-giup-mk-vs-a-huhu.2030470567354

làm hết r mà :vv

Good