bài 2 

a] = 3 x \(\frac{4343}{7171}\)= \(\frac{17372}{7171}\)= \(\frac{172}{71}\)

b] = \(\frac{1}{33}\)x \(\frac{44}{7}\)= \(\frac{1}{3}\)x \(\frac{4}{7}\)=\(\frac{4}{21}\)

bài 1 

a] y là 9

b] <=> 64y + 36y = 700 - 75 - 225

<=> 100y = 400

<=> y = 4

trên lớp cô sửa rồi nên mình giải luôn:

1) Tìm y

a) y3 + 3y = 12 x 11

    y3 + 3y = 132

    y x 10 + 3 + 3 x 10 + y = 132

   ( y x 10 + y ) + ( 3 x 10 + 3 ) = 132

     11 x y + 33 = 132 

     11 x y = 132 - 33

     11 x y = 99

            y = 99 : 11

            y = 9

b) 64 x y + 225 = 700 - 75 - 36 x y

    64 x y + 225 = 625 - 36 x y

    64 x y + 36 x y = 625 -225

    64 x y + 36 x y = 400

    ( 64 + 36 ) x y = 400

    100 x y = 400

              y =  400 : 100

              y = 4

2) Tính

a) \(\frac{4343}{7171}+\frac{4343}{7171}+\frac{4343}{7171}+\frac{4343}{7171}\)

\(=\frac{4343}{7171}\times4\)

\(=\frac{43}{71}\times4\)

\(=\frac{172}{71}\)

b) A = \(\frac{1}{33}\times\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)\)

   Ta có:

   \(\frac{3333}{2020}=\frac{3333:101}{2020:101}=\frac{33}{20}\)

   \(\frac{333333}{303030}=\frac{333333:10101}{303030:10101}=\frac{33}{30}\)

  \(\frac{33333333}{42424242}=\frac{33333333:1010101}{42424242:1010101}=\frac{33}{42}\)

   A = \(\frac{1}{33}\times\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)\)

   A = \(\frac{1}{33}\times33\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)

  A = 1 x \(\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)

  A = 1 x \(\left(\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}\right)\)

  A = 1 x \(\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)

  A = 1 x \(\left(\frac{1}{3}-\frac{1}{7}\right)\)

  A = 1 x \(\left(\frac{7}{21}-\frac{3}{21}\right)\)

  A = 1 x \(\frac{4}{21}\)

  A = \(\frac{4}{21}\)

\(a,-\dfrac{4}{5}=-0,8\) \(;\dfrac{2}{10}=0,2\) \(\Rightarrow\) Ko bằng nhau

\(b,\dfrac{3}{2}=1,5;\dfrac{9}{6}=\dfrac{3}{2}=1,5\Rightarrow\) Bằng nhau

\(c,\dfrac{1}{-2}=-0,5;-\dfrac{40}{80}=-\dfrac{1}{2}=-0,5\Rightarrow\) Bằng nhau

\(d,-\dfrac{12}{5}=-2,4;-\dfrac{144}{25}=-5,76\Rightarrow\) Ko bằng nhau

\(e,\dfrac{2525}{4343}=\dfrac{25}{43};\dfrac{25}{43}=\dfrac{25}{43}\)\(\Rightarrow\) Bằng nhau

\(f,-\dfrac{26}{17}\approx-1,53;\dfrac{262626}{171717}=\dfrac{26}{17}\approx1,53\) \(\Rightarrow\) Ko bằng nhau

Ta có: 15x14-1/15x13+14=15x13+15-1/15x13+14=15x13+14/15x13+14=1 

\(\frac{15x14-1}{15x13+14}\)

\(\frac{15x13}{15x13+14}\)=\(\frac{1}{14}\)

a,

\(=\frac{1+2+3+4+5+6+7+8+9}{10}=\frac{45}{10}=\frac{9}{2}\)

b,\(=9\times\left(\frac{26\times10101}{27\times10101}+\frac{8\times11111}{9\times11111}\right)=9\times\left(\frac{26}{27}+\frac{8}{9}\right)=9\times\frac{50}{27}=\frac{50}{3}\)

k cho mk nha!!!!!!!!!!!!!

Mk cần gấp các bạn ơi !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!?

Bằng 3/142

\(\frac{3434}{7171}+x=\frac{1234}{2468}\)

\(\frac{34}{71}+x=\frac{1}{2}\)

\(x=\frac{1}{2}-\frac{34}{71}\)

\(x=\frac{3}{142}\)

a) \(\frac{27.45+55.27}{2+4+6+8+...+16+18}=\frac{27.\left(45+55\right)}{\left(2+18\right)+\left(16+4\right)+\left(14+6\right)+\left(12+8\right)}\)

\(=\frac{27.100}{20+20+20+20}=\frac{2700}{20.4}=\frac{2700}{80}=\frac{135}{4}\)

b) Lười

Làm giống câu a nhé

xin lỗi! mik ko rảnh

C  = \(\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)

\(C=\frac{\left(101+1\right).101:2}{1+1+...+1+1}\)

\(C=\frac{5151}{51}\)

\(C=101\)

b) \(D=\frac{3737.43-4343.37}{2+4+6+...+100}\)

\(D=\frac{37.101.43-43.101.37}{2+4+6+...+100}\)

\(D=\frac{0}{2+4+6+...+100}\)

\(D=0\)

a)C=101

b)d=0

Trả lời

3737.43-4343.37/2+4+6+...+100

=37.101.43-43.101.37/2+4+6+...+100

=0/100

=0

Chúc bạn học tốt !

Cái này có dấu hiệu nè , bạn nên nhớ số có dạng \(\overline{abab}\)đề chia hết cho \(\overline{ab}\)và 101 nha

3737.43-4343.37/2+4+6+...+100

=37.101.34-43.101.37/2+4+6+...+100

=0/2+4+6+...+100

=0

Hok tốt !

\(\frac{3737.43-4343.7}{2+4+6+...+100}\)

\(=\frac{37.101.43-4343.37}{2+4+6+...+100}\)

\(=\frac{37.4343-4343.37}{2+4+6+...+100}\)

\(=\frac{0}{2+4+6+...+100}\)

Ta có : Tử số bằng 0 \(\Rightarrow\) phân số trên bằng 0

\(=0\)

\(\frac{3737.43-4343.7}{2+4+6+....+100}\)

=\(\frac{37.101.43-4343.37}{2+4+6+...+100}\)

\(=\frac{37.4343-4343.37}{2+4+6+....+100}\\ =\frac{0}{2+4+6+...+100}\\ =0\)