tìm X
X+X+X+X+X =100
X+X+X+X *5 = 200
(X+1) + (X+4) +(X+7) + (X+10) =62
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a) 2 x 2 = 4 3 x 3 = 9
2 x 4 = 8 3 x 5 = 15
2 x 6 = 12 3 x 7 = 21
2 x 8 = 16 3 x 9 = 27
4 x 4 = 16 5 x 5 = 25
4 x 2 = 8 5 x 7 = 35
4 x 6 = 24 5 x 9 = 45
4 x 8 = 32 5 x 3 = 15
b) 200 x 4 = 800 300 x 2 = 600
200 x 2 = 400 300 x 3 = 900
400 x 2 = 800 500 x 1 = 500
100 x 4 = 400 100 x 3 = 300
(x+1)+(x+4)+(x+7)+(x+10)=62
=>4x+22=62
=>4x=62-22
=>4x=40
=>x=10
t tôi nha bn
(x+1)+(x+4)+(x+7)+(x+10)=62
( x + x + x + x ) + ( 1 + 4 + 7 + 10 ) = 62
4x + 22 = 62
4x = 62 - 22
4x = 40
x = 40 : 4
x = 10
(x + 1) + (x + 4) + (x + 7) + (x + 10) = 62
x + 1 + x + 4 + x + 7 + x + 10 = 62
4x + 22 = 62
4x = 40
=> x = 40 / 10 = 4
\(\left(x+1\right)+\left(x+4\right)+\left(x+7\right)+\left(x+10\right)=62\)
\(\Rightarrow x+1+x+4+x+7+x+10=62\)
\(\Rightarrow4x+22=62\)
\(\Rightarrow4x=40\)
\(\Rightarrow x=10\)
a, 35 ⋮ (x+3) => (x+3) ∈ Ư(35) = {1;5;7;35} => x ∈ {2;4;32}
b, (x+7) ⋮ 25 và x < 100
Vì (x+7) ⋮ 25 => x+7 ∈ B(25) = {0;25;50;75;...}
Mà x < 100 => x+7 ∈ {0;25;50;75}
=> x ∈ {18;43;68}
c, (x+13) ⋮ (x+1)
Ta có: x+13 = x+1+12
Vì (x+1) ⋮ (x+1) nên để (x+13) ⋮ (x+1) thì 12 ⋮ (x+1)
=> (x+1) ∈ Ư(12) = {1;2;3;4;6;12} => x ∈ {0;1;2;3;5;11}
d, 91 ⋮ x; 26 ⋮ x và 10 < x < 30
Vì 91 ⋮ x; 26 ⋮ x => x ∈ ƯC(26;91)
Ta có: 26 = 2.13; 91 = 7.13
=> ƯCLN(26;91) = 13
=> x ∈ Ư(13) = {1;13}
Mà 10 < x < 30 => x = 13
e, (x+2) ⋮ 10, (x+2) ⋮ 15, (x+2) ⋮ 25 và x < 200
Vì (x+2) ⋮ 10, (x+2) ⋮ 15, (x+2) ⋮ 25 nên (x+2) ∈ BC(10;15;25)
Ta có: 10 = 2.5; 15 = 3.5; 20 = 2 2 . 5
=> BCNN(10;15;20) = 2 2 . 3 . 5 = 60
=> (x+2) ∈ B(60) = {0;60;120;180;...}
Mà x < 200 => x ∈ {58;118;178}
a) x2 + x = 0
=> x( x+ 1 ) = 0
=> x = 0
hoặc x = -1
b) b, (x-1)x+2 = (x-1)x+4
=> x + 2 = x + 4
=> 0x = 2 ( ktm)
Vậy ko có giá trị x nào thoả mãn đk
d) Ta có: x-1/x+5 = 6/7
=>(x-1).7 = (x+5).6
=>7x-7 = 6x+ 30
=> 7x-6x = 7+30
=> x = 37
Vậy x = 37
e, x2/ 6= 24/25
=> x2 . 25 = 6 . 24
⇒
Vậy
\(200:25-\left(12-x\right)=4\\ 8-\left(12-x\right)=4\\ 12-x=8-4\\ 12-x=4\\ x=12-4\\ x=8\\ ---\\ \left(x-10\right).5=100-20.4\\ \left(x-10\right).5=100-80=20\\ x-10=\dfrac{20}{5}=4\\ x=4+10=14\)
a)\(200:25-\left(12-x\right)=4\)
\(\Rightarrow8-\left(12-x\right)=4\)
\(\Rightarrow12-x=8-4\)
\(\Rightarrow12-x=4\)
\(\Rightarrow x=12-4\)
\(\Rightarrow x=8\)
b) \(\left(x-10\right)\cdot5=100-20\cdot4\)
\(\Rightarrow\left(x-10\right)\cdot5=100-80\)
\(\Rightarrow\left(x-10\right)\cdot5=20\)
\(\Rightarrow x-10=4\)
\(\Rightarrow x=10+4\)
\(\Rightarrow x=14\)
x+x+x+x+x=100⇔5x=100⇔x=100:5=20
\(x\) + \(x\) + \(x\) + \(x\) = 100
\(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\)1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1 = 100
\(x\) \(\times\) ( 1 + 1 + 1 + 1 + 1 ) = 100
\(x\) \(\times\) 5 = 100
\(x\) = 100 : 5
\(x\) = 20
\(x\) + \(x\) + \(x\) + \(x\) \(\times\) 5 = 200
\(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\)1 + \(x\) \(\times\) 5 = 200
\(x\) \(\times\) ( 1 + 1 + 1 + 5) = 200
\(x\) \(\times\) 8 = 200
\(x\) = 200 : 8
\(x\) = 25
(\(x\) + 1) + (\(x\) + 4) + ( \(x\) + 7) + (\(x\) + 10) = 62
\(x\) + 1 + \(x\) + 4 + \(x\)+ 7 + \(x\) + 10 = 62
( \(x\) + \(x\) + \(x\) + \(x\) ) + ( 1 + 4 + 7 + 10) = 62
( \(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1) + 22 = 62
\(x\) \(\times\) ( 1 + 1 + 1 + 1) + 22 = 62
\(x\) \(\times\) 4 + 22 = 62
\(x\) \(\times\) 4 = 62 - 22
\(x\) \(\times\) 4 = 40
\(x\) = 40 : 4
\(x\) = 10